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# trigonometry watch

1. How does cos^2X + 4sin^2X / cos^2X = 7 become 1 + (4sin^2X / cos^2X) = 7
Thanks
2. I'm assuming you meant (cos^2X + 4sin^2x)/cos^2x = 7, ie. that both cos^2x and 4sin^2x are in the numerator of the fraction.

You can separate the fraction into two parts --> cos^2x/cos^2x + 4sin^2x/cos^2x = 7. Something divided by itself is always equal to one, so:
1 + (4sin^2x/cos^2x )= 7
3. &
(Original post by suwuken)
I'm assuming you meant (cos^2X + 4sin^2x)/cos^2x = 7, ie. that both cos^2x and 4sin^2x are in the numerator of the fraction.

You can separate the fraction into two parts --> cos^2x/cos^2x + 4sin^2x/cos^2x = 7. Something divided by itself is always equal to one, so:
1 + (4sin^2x/cos^2x )= 7
Yeah i did mean that, sorry should have made it clearer, and that makes sense, thanks
4. (Original post by daviem)
&

Yeah i did mean that, sorry should have made it clearer, and that makes sense, thanks
No worries, glad I could help

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