doing a past paper, a question asked what would happen when Cl2 and NaOH reacted, one of the products being NaClO. the answer was:
2NaOH + Cl2 ---> NaClO + NaCl + H2O why is this the answer? I got it wrong as i put the products as NaClO and HCL, with only one mol of NaOH
please help!!!
It's a disproportionation reaction so the products will be NaCLO NaCL and H2O. There will always be three products for this reaction not two like you put
doing a past paper, a question asked what would happen when Cl2 and NaOH reacted, one of the products being NaClO. the answer was:
2NaOH + Cl2 ---> NaClO + NaCl + H2O why is this the answer? I got it wrong as i put the products as NaClO and HCL, with only one mol of NaOH
please help!!!
Think of it like this: You're told that when the Cl2 and NaOH react, one of the products is NaClO. That means that the remaining products are a H+ ion and a Cl- ion. These two ions will bond, forming hydrogen chloride (HCl) also known as hydrochloric acid. But when one Cl2 and NaOH react, to form a HCl, there's still more of the NaOH present in the solution, so the HCl will react with the NaOH (neutralisation reaction) to form NaCl and H2O, therefore ending up with NaClO, NaCl, and H2O!