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C2 integration

Im struggling with this question.
Original post by Kadak
Im struggling with this question.


Add 1 to both sides then square both sides



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Get the square root by itself on one side of the equation, and then square everything.
Original post by ghostwalker
Get the square root by itself on one side of the equation, and then square everything.




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Did that,but where does the 2y come from?
Original post by Kadak
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Did that,but where does the 2y come from?


None of your attempts show you doing that. What did you get?
Original post by ghostwalker
None of your attempts show you doing that. What did you get?




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Original post by Kadak
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Did that,but where does the 2y come from?


(Y+1)^2


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You can't square y and 1 separately you have to do (y+1) ^2


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When you square one side of the equation you are squaring one thing, that is the "y+1", hence (y+1)2(y+1)^2. You can't just square the y term and square the 1 and add them.
Original post by samb1234
You can't square y and 1 separately you have to do (y+1) ^2


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Why can't I square them separately? They aren't together? :confused.
Original post by Kadak
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Why can't I square them separately? They aren't together? :confused.


Yes they are. Say for example you had something equal to 1+2. If you square them separately and added you would get 5 when clearly it is 3^2 ie 9


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Original post by samb1234
Yes they are. Say for example you had something equal to 1+2. If you square them separately and added you would get 5 when clearly it is 3^2 ie 9


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Oh.Ok,Ty, I never knew that.
What's the answer for the second part?
Original post by sofburgos
What's the answer for the second part?




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I'm doing it now.Sorry it took so long,I just had breakfast and Ben and jerry Ice cream.
Reply 15
expand (y+1)^2
you square y+1 because the other side everything is rooted.
(edited 8 years ago)
Original post by sofburgos
What's the answer for the second part?




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Its 32/3.

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