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    See attached image.

    King regards
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    :bump::bump:.
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    (Original post by hajs)
    :bump::bump:.
    Arithmetic slip somewhere

    CA=(-3,-6,-3)

    CB=(-10,0,-4)

    Giving 42/sqrt(116x54)
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    (Original post by ghostwalker)
    Arithmetic slip somewhere

    CA=(-3,-6,-3)

    CB=(-10,0,-4)

    Giving 42/sqrt(116x54)
    Oh! Wait, so do you get that from doing (A)-(C) ?
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    (Original post by hajs)
    Oh! Wait, so do you get that from doing (A)-(C) ?
    To get CA, yes.
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    (Original post by ghostwalker)
    To get CA, yes.
    Omg ahahha I realised what I did now! Thank you!!!
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    Isnt is 1/lambda sin(lambdaT)
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    (Original post by hajs)

    Isnt is 1/lambda sin(lambdaT)
    if you can differentiate the second line to get the first line then it is good.
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    (Original post by the bear)
    if you can differentiate the second line to get the first line then it is good.
    How would i do it without knowing the second line?:confused:
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    (Original post by hajs)

    Isnt is 1/lambda sin(lambdaT)
    Lamba is a constant.
    If you place it outside the integral then yes you are correct you get 1/lambda sin(lambdaT). But when you multiply back in the lambda that you placed outside the integral then they cancel so you are left with line 2.
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    (Original post by LouN1997)
    Lamba is a constant.
    If you place it outside the integral then yes you are correct you get 1/lambda sin(lambdaT). But when you multiply back in the lambda that you placed outside the integral then they cancel so you are left with line 2.
    From where? I didnt place nothing outside..
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    OHHHHH.
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    Hahah Silly me, THANKS!! +Rep. :thumbsup::thumbsup:
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    if you have to integrate a fraction:

    always check to see if the top is the derivative ( dy/dx ) of the underneath. if so the the answer is ln|underneath| + c

    here 1 is the derivative of p ...

    on the RHS you could do a substitution: let W = λt
 
 
 
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