OCR MEI C3 Maths June 2015

Your papers look so much harder than ours

Didn't do this exam (I do edexcel), but I like snooping on other papers. Here's how I would do 6b)

Arcsin(x))=arccos(x)

Cos(arcsin(x))=x

Sin(90-arcsin(x))=x

90-arcsin(x)=arcsin(x)

Then solve for x like this

Neat

I think finding the derivative is worth 3 marks. 1 mark for verifying (1, 1) and 1 mark for substituting in (1, 1) and obtaining the correct answer.

Another alternative is 1 for verify. 2 for derivative (both method). 1 method for subbing in (1, 1). 1 accuracy for answer = 1/2

What do you guys think the boundaries will be like for an A? 58 ? Or higher ?

58 at max many on these thread are those pupils who are aiming at A*s A's as you can see by comments; i'd say 2 mark lower than last yrs

I definitely verified the point satisfied the equation so I should get marks for it.

I might have differentiated correctly and gotten 1/2 but how many marks would I lose for

Differentiated incorrectly and therefore got a gradient that was not 1/2 would I still get marks for attempting?

Differentiated correctly but substituting (1,1) wrong and not getting 1/2 would I only lose one accuracy Mark?


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isnt there a asymptote at x=3 therefore the domain for f(x) should be ln2<=x<3

No the asymptote would have been at x=-3 if extended beyond ln2

Didn't do this exam (I do edexcel), but I like snooping on other papers. Here's how I would do 6b)

Arcsin(x))=arccos(x)

Cos(arcsin(x))=x

Sin(90-arcsin(x))=x

90-arcsin(x)=arcsin(x)

Then solve for x like this

I'm 100% sure there are no asymptotes to f(x).

How many marks for doing

Cos(arcsin(x))=x?Plus, I attempted to draw inverse graphs of cos and sin (which took so long) lol.. which was in vain.

My teacher said (he has done MEI over 10 years or something) that your coursework marks can go down or up very easily as the examiner mark each one (I think if you are a class under 20 the schools require to sent the courseworks off) is this true?