Stability of Alkenes
In one Elimination reaction, why was the first product favoured more?
It's not due to E/Z isomers. Is it to do with alternate double bonds giving more stability maybe?
It's not due to E/Z isomers. Is it to do with alternate double bonds giving more stability maybe?
Yes; there is a thermodynamic drive towards conjugation in the product.
There would also be a stereo electronic preference for the abstraction of the proton adjacent to the double bond, hence providing a lower free energy barrier for the transition state.
Original post by Infraspecies
Yes; there is a thermodynamic drive towards conjugation in the product.
Original post by Infraspecies
There would also be a stereo electronic preference for the abstraction of the proton adjacent to the double bond, hence providing a lower free energy barrier for the transition state.
Very clear, as usual. Thanks a bunch!
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