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    In one Elimination reaction, why was the first product favoured more?
    It's not due to E/Z isomers. Is it to do with alternate double bonds giving more stability maybe?
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    Yes; there is a thermodynamic drive towards conjugation in the product.
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    There would also be a stereo electronic preference for the abstraction of the proton adjacent to the double bond, hence providing a lower free energy barrier for the transition state.
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    (Original post by Infraspecies)
    Yes; there is a thermodynamic drive towards conjugation in the product.
    (Original post by Infraspecies)
    There would also be a stereo electronic preference for the abstraction of the proton adjacent to the double bond, hence providing a lower free energy barrier for the transition state.
    Very clear, as usual. Thanks a bunch!
 
 
 
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