Help? Probability Question- S1Watch

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#1
Hey there, I am completing this booklet on probability questions and there is this specific ones which I just can't seem to wrap my head around it >.<

I have been stuck here for quite some time now, so any help would be greatly appreciated! ^>^ (Please be clear on the explanation )
________________________________ _____

Q1: Two events R are such that :

P(RnQ')= 0.15 P(Q)=0.35 P(R l Q)=0.1

b) Find the value of P(RUQ)

C) P(RnQ)

D) P(R)
________________________________ ______
0
4 years ago
#2
(Original post by FloralEssence)
Hey there, I am completing this booklet on probability questions and there is this specific ones which I just can't seem to wrap my head around it >.<

I have been stuck here for quite some time now, so any help would be greatly appreciated! ^>^ (Please be clear on the explanation )
________________________________ _____

Q1: Two events R are such that :

P(RnQ'= 0.15 P(Q)=0.35 P(R l Q)=0.1

b) Find the value of P(RUQ)

C) P(RnQ)

D) P(R)
________________________________ ______
I suggest you draw a Venn diagram, then you would see
Spoiler:
Show
1
4 years ago
#3
P(R I Q) = P(RnQ) / P(Q) = 0.1 Therefore P(RnQ) = 0.1 X 0.35 = 0.035 (The intersection in the centre of a Venn Diagram)

P(RnQ') = 0.15 In a Venn Diagram this is R but excluding the centre intersection with Q. Therefore P(R) = P(RnQ') + P(RnQ) = 0.15 + 0.035 = 0.185

P(RUQ) = 0.15 + 0.035 + 0.315 = 0.5 so 0.5 must be outside the Venn Diagram circles.
2
#4
(Original post by nahnah27)
P(R I Q) = P(RnQ) / P(Q) = 0.1 Therefore P(RnQ) = 0.1 X 0.35 = 0.035 (The intersection in the centre of a Venn Diagram)

P(RnQ' = 0.15 In a Venn Diagram this is R but excluding the centre intersection with Q. Therefore P(R) = P(RnQ' + P(RnQ) = 0.15 + 0.035 = 0.185

P(RUQ) = 0.15 + 0.035 + 0.315 = 0.5 so 0.5 must be outside the Venn Diagram circles.
Thank you ever so much! ^>^ *Rep*
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