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Cant do this chemistry question

AgCl(s) → Ag+(aq) + Cl–(aq)
The solubility product (Ks) for silver chloride
is given by the expression Ks= [Ag+(aq)] [Cl–(aq)]

The formula mass of AgCl is 143·4.
Ks
= 1·80 × 10–10 at 25 °C.
The solubility of silver chloride, in mol l–1, at
25 °C is

A 1·80 × 10–10
B 3·60 × 10–10
C 1·34 × 10–5
D 2·68 × 10–5.

Please explain also
Reply 1
Avatar for Pigster
Pigster
20
When AgCl dissolves, 1 Mol of AgCl -> 1 mol Ag+(aq) and 1 mol of Cl-(aq)

Given Ks, you can calculate [Aq+] (which will be the same as [Cl-].

From that you can work out what the [AgCl(aq)] is.

I don't see the need for Mr.
Original post by Pigster
When AgCl dissolves, 1 Mol of AgCl -> 1 mol Ag+(aq) and 1 mol of Cl-(aq)

Given Ks, you can calculate [Aq+] (which will be the same as [Cl-].

From that you can work out what the [AgCl(aq)] is.

I don't see the need for Mr.


Thanks for your time

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