Rearranging difficult formula

OP

Original post by muchensmile

Hi, I think the answer is T=1/2(2/(w^2-3/2))

This is the answer.

Reply 5

Yammy

15

sorry got the 2 and 7 confused should be this T=1/2(7/(w^2-3/2))
times bottom bracket out by 2 and you get the answer

Reply 6

OP

Original post by mk96

W^2 = (3t+7)/2t
2t*w^2 = 3t+ 7
2t*w^2 - 3t = 7
t(2w^2 - 3) = 7
t = 7/(2w^2 - 3)

Oh wow thank you guys. That's exactly what I done. But I factorised it wrong. I factorised it without the 2w^2 and hence why I got it wrong.
Thanks guys, you lot are extremely helpful!
I'll work on looking at the terms I multiplied the other term with properly.

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Reply 7

OP

1 more question. I don't understand how the answer to this question is 4/3 π r^3 - volume of a sphere.
Is it because the basque is shared by both shapes in the solid and therefore you don't have to add the extra π r^2.
And that is why you only multiply the height which is 2r and it makes the answer.
2/3 π r ^2 * 2r = 4/3 π r^3. Am I right?

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(edited 8 years ago)

Reply 8

the bear

Original post by Chittesh14

1 more question. I don't understand how the answer to this question is 4/3 π r^3 - volume of a sphere.
Is it because the basque is shared by both shapes in the solid and therefore you don't have to add the extra π r^2.
And that is why you only multiply the height which is 2r and it makes the answer.
2/3 π r ^2 * 2r = 4/3 π r^3. Am I right?

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they are not asking about the area... it is volume

Reply 9

OP

Original post by the bear

they are not asking about the area... it is volume

I know, that's why I was wondering that it couldn't be the base is shared by both of them as this is the volume. But, I count figure it out :O. Today is not my day for maths lol

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Reply 10

the bear

the hemisphere is 2⁄3πr³

the cone is 1⁄3πr²h

let h = 2r...

Reply 11

OP

Original post by the bear

the hemisphere is 2⁄3πr³

the cone is 1⁄3πr²h

let h = 2r...

1⁄3πr²2r + 2⁄3πr³ = 4/3πr³?

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Reply 12

the bear

Original post by Chittesh14

1⁄3πr²2r + 2⁄3πr³ = 4/3πr³?

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well you have to convince yourself...

Reply 13

OP

Original post by the bear

well you have to convince yourself...

Sorry the question mark was an accident, I get it, I was multiplying the powers and got r^5. What I meant is how could I not understand this any earlier, like how did I get this wrong... :P.
Thanks :smile:

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Reply 14

Muttley79