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An excess of silver nitrate solution is addedto a solution of sodium chloride,and a whiteprecipitate is formed. The precipitate is then filtered off.
Which solution would not give a precipitate when added to the filtrate?
A Barium chloride
B Potassium nitrate
C Calcium iodide
D Sodium bromide
I know the answer but can someone explain it and how to get the answer thanks
Which solution would not give a precipitate when added to the filtrate?
A Barium chloride
B Potassium nitrate
C Calcium iodide
D Sodium bromide
I know the answer but can someone explain it and how to get the answer thanks
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#2
It is B I think,
When adding AgNO3 to XCl you get a white precipitate.
When adding to XBr you get a cream precipitate
When adding to XI you get a yellow precipitate.
B must be the answer by elimination.
You need to learn these colours for your exam and what happens to the precipitate when dilute/concentrated ammonia is added
When adding AgNO3 to XCl you get a white precipitate.
When adding to XBr you get a cream precipitate
When adding to XI you get a yellow precipitate.
B must be the answer by elimination.
You need to learn these colours for your exam and what happens to the precipitate when dilute/concentrated ammonia is added
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#3
So, the reaction is AgNO3 added to NaCl, which reacts, giving us a white precipitate (AgCl) and leaving us with the filtrate (NaNO3).
I'd agree it is B, seeing how adding KNO3 to NaNO3 shouldn't result in any reaction at all.
I'd agree it is B, seeing how adding KNO3 to NaNO3 shouldn't result in any reaction at all.
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#4
You need to know that from the halide test, ANY halogen that reacts with AgNO3 will make a precipitate, and as the only one on there that doesn't contain a halogen is B, then it must be B
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