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C4 binomial q

I'm stuck on part (c), I have tried setting root5 equal to 1/(1+2x)^-1/2 but that gives me -0.1, which is what is given, but I don't know what to sub that into because when I sub it into the expansion for 1/(1+2x)^-1/2 I don't get 2.23
Original post by mica-lwe
I'm stuck on part (c), I have tried setting root5 equal to 1/(1+2x)^-1/2 but that gives me -0.1, which is what is given, but I don't know what to sub that into because when I sub it into the expansion for 1/(1+2x)^-1/2 I don't get 2.23


If you sub x=0.1x=-0.1 into your expression you'll get 10.8\dfrac{1}{\sqrt{0.8}}

=1.25=54=52=\sqrt{1.25}= \sqrt{\frac{5}{4}}=\frac{\sqrt{5}}{2}

So, whatever your expansion works out to, you'll need to double it to get the approximation of 5\sqrt{5}
Reply 2
Original post by ghostwalker
If you sub x=0.1x=-0.1 into your expression you'll get 10.8\dfrac{1}{\sqrt{0.8}}

=1.25=54=52=\sqrt{1.25}= \sqrt{\frac{5}{4}}=\frac{\sqrt{5}}{2}

So, whatever your expansion works out to, you'll need to double it to get the approximation of 5\sqrt{5}


Thank you :smile: I was overthinking it too much :K:

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