Zeus579
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Can someone explain e)ii) to me please
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Zeus579
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http://www.ocr.org.uk/Images/131287-...-resources.pdf
(Original post by Zeus579)
Can someone explain 4e)ii) to me please
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Millahat
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Okay, so the question is asking for the Enthalpy change of formation of N2O

They give you the enthalpy changes for the FORWARD reaction of C + N2O --> CO and N2 (-193)

And the enthalpy change for making CO (-111)

Now, if you look at the first reaction, you can practically forget about C and N2 as they are elements (which have an enthalpy change of 0)

That done, it makes sense that to find the enthalpy change of N2O you would minus -111 from -193 HOWEVER remember that the -193 is the change for the FORWARD reaction, and N2O is a reactant so you would REMOVE the - sign.

Then... 193-111= +82

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Hope this helped... Typed it on my phone so it might be a bit confusing :/



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