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M1 Equilibrium/Statics Question - Where have I gone wrong?

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edexcel sending.jpg

I can do the rest except part A

I must of accidentally cut of the last line but basically I managed to get R=55N
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Reply 1
Avatar for a10
a10
19
Original post by creativebuzz
Untitled.png

Attachment not found
Attachment not found
edexcel sending.jpg

I can do the rest except part A

I must of accidentally cut of the last line but basically I managed to get R=55N


Where is the friction force in your calculation?

Edit: nvm ive seen it, youre image is blurry.
(edited 8 years ago)
Original post by a10
Where is the friction force in your calculation?

Edit: nvm ive seen it, youre image is blurry.


Yeah sorry about that! But yeah it's there somewhere :P
Reply 3
Avatar for a10
a10
19
Original post by creativebuzz
Yeah sorry about that! But yeah it's there somewhere :P


I got the reaction to be 27.61N? Not sure if thats right though...

Calculate P first:

P = m (gMcos30 + gsin30)/ (-Msin30 -cos30)

P was negative

Then sub back into the equation:

N = mgcos30 + Psin30

I used big M for mew lol cba to type it all on latex
(edited 8 years ago)
Original post by a10
I got the reaction to be 27.61N? Not sure if thats right though...

Calculate P first:

P = m (gMcos30 + gsin30)/ (-Msin30 -cos30)

P was negative

Then sub back into the equation:

N = mgcos30 + Psin30

I used big M for mew lol cba to type it all on latex


No worries, Ive got the answer now (R=74.7)
Reply 5
Avatar for a10
a10
19
Original post by creativebuzz
No worries, Ive got the answer now (R=74.7)


Oops apologies just realised the question said moving up so the direction of friction was the other way round to what i had drawn changing the value of P to be +ve instead and hence giving R=74N! :smile:

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