# WJEC maths calc

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Have created this thread so answers can be posted and so people can discuss the exam

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(Original post by

it was a good exam

**ibrahimyusuf**)it was a good exam

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#4

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I agree, although I think paper one was a bit easier. The fact the exam wasn't too bad unfortunately means higher grade boundaries though. What grade do you think you'll get overall.

**G98**)I agree, although I think paper one was a bit easier. The fact the exam wasn't too bad unfortunately means higher grade boundaries though. What grade do you think you'll get overall.

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A* most probably. The circle theorems and the last question were the trickiest, what did you get for those?

**jamesalsbury**)A* most probably. The circle theorems and the last question were the trickiest, what did you get for those?

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#6

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I felt like I've probably got an A* or if not an A. For the last question I got 2.79 to 2.d.p. but I didn't even attempt any of the circle theorem questions as I didn't have enough time. What did you get for the quadratic formula question-I got 4.13 to 2d.p.

**G98**)I felt like I've probably got an A* or if not an A. For the last question I got 2.79 to 2.d.p. but I didn't even attempt any of the circle theorem questions as I didn't have enough time. What did you get for the quadratic formula question-I got 4.13 to 2d.p.

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The last question was 3.4 to 1d.p. but it took me absolutely ageees, the circle theorems were tricky, don't think i got all of them. The last circle theorem was trigonometry in disguise. Yeah that quadratic one's right, the answers were 4.13 and -7.13

**jamesalsbury**)The last question was 3.4 to 1d.p. but it took me absolutely ageees, the circle theorems were tricky, don't think i got all of them. The last circle theorem was trigonometry in disguise. Yeah that quadratic one's right, the answers were 4.13 and -7.13

okay, thanks. I'm not sure you had to the quadratic formula for the plus or minus though as it was only worth three marks, but there again it's better to be safe than sorry. How did you get 3.4 to 1d.p. The question also asked to give your answer to 2 decimal places.

I did (1/3*pi*r2*h) + (pi*r2*h)=245cm3

so r2= 245/ (1/3*pi*h) + (pi*h)

so r= square root 245/ (1/3*pi*h) + (pi*h)

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#8

(Original post by

okay, thanks. I'm not sure you had to the quadratic formula for the plus or minus though as it was only worth three marks, but there again it's better to be safe than sorry. How did you get 3.4 to 1d.p. The question also asked to give your answer to 2 decimal places.

I did (1/3*pi*r2*h) + (pi*r2*h)=245cm3

so r2= 245/ (1/3*pi*h) + (pi*h)

so r= square root 245/ (1/3*pi*h) + (pi*h)

**G98**)okay, thanks. I'm not sure you had to the quadratic formula for the plus or minus though as it was only worth three marks, but there again it's better to be safe than sorry. How did you get 3.4 to 1d.p. The question also asked to give your answer to 2 decimal places.

I did (1/3*pi*r2*h) + (pi*r2*h)=245cm3

so r2= 245/ (1/3*pi*h) + (pi*h)

so r= square root 245/ (1/3*pi*h) + (pi*h)

And type this '(π*r^2*5.4)+(π*(1/3)*r^2*4.2)=245' into the search bar, the answer is 3.38.

I don't remember it saying to 2 decimal places but it's only one mark lost if it did, thank you anyway.

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(Original post by

Go on to; http://www.mathpapa.com/algebra-calculator.html

And type this '(π*r^2*5.4)+(π*(1/3)*r^2*4.2)=245' into the search bar, the answer is 3.38.

I don't remember it saying to 2 decimal places but it's only one mark lost if it did, thank you anyway.

**jamesalsbury**)Go on to; http://www.mathpapa.com/algebra-calculator.html

And type this '(π*r^2*5.4)+(π*(1/3)*r^2*4.2)=245' into the search bar, the answer is 3.38.

I don't remember it saying to 2 decimal places but it's only one mark lost if it did, thank you anyway.

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**jamesalsbury**)

Go on to; http://www.mathpapa.com/algebra-calculator.html

And type this '(π*r^2*5.4)+(π*(1/3)*r^2*4.2)=245' into the search bar, the answer is 3.38.

I don't remember it saying to 2 decimal places but it's only one mark lost if it did, thank you anyway.

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#11

(Original post by

Also, what did you get for the question which asked for all the possible solutions for sin x=-829 or something like that

**G98**)Also, what did you get for the question which asked for all the possible solutions for sin x=-829 or something like that

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It seems like you knew the method but just made some silly mistake in there so i'm sure you'll get 4/5 on that one. I'm glad the sin graph was on the calculator paper, it's so much easier with a calculator, I got x = 236 and x= 304

**jamesalsbury**)It seems like you knew the method but just made some silly mistake in there so i'm sure you'll get 4/5 on that one. I'm glad the sin graph was on the calculator paper, it's so much easier with a calculator, I got x = 236 and x= 304

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#13

(Original post by

Same, I was so glad there was a calculator. I know I drew the sin graph right, but I didn't have a clue to work out the possible solutions to this equation. I'm sure the teacher never went through this with us, but anyway I just assumed the answer was 90 because sin 90 equalled 1 which would give the same answer as -289 or whatever it was when it was multiplied. How did you work this out.

**G98**)Same, I was so glad there was a calculator. I know I drew the sin graph right, but I didn't have a clue to work out the possible solutions to this equation. I'm sure the teacher never went through this with us, but anyway I just assumed the answer was 90 because sin 90 equalled 1 which would give the same answer as -289 or whatever it was when it was multiplied. How did you work this out.

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(Original post by

Trial and error. From my graph I knew the answer was between 180 and 270 so I tried all the values from 180 to 236 until I got the right one. Then 270-236 = 34 and I knew there was always a pattern so 270+34 = 304 so my two answers were 304 and 236. After i'd got the answers on the calculator I just drew lines on the graph to look like i'd read off the graph.

**jamesalsbury**)Trial and error. From my graph I knew the answer was between 180 and 270 so I tried all the values from 180 to 236 until I got the right one. Then 270-236 = 34 and I knew there was always a pattern so 270+34 = 304 so my two answers were 304 and 236. After i'd got the answers on the calculator I just drew lines on the graph to look like i'd read off the graph.

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#15

(Original post by

Thanks so much, I get it now. What do you reckon the grade boundaries will be this year?

**G98**)Thanks so much, I get it now. What do you reckon the grade boundaries will be this year?

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(Original post by

Excellent.

And i think overall the papers were about the same difficulty as normal so i'd expect 140/145 for an A*, 115/120 for an A, 100 for a B, 75/80 for a C

**jamesalsbury**)Excellent.

And i think overall the papers were about the same difficulty as normal so i'd expect 140/145 for an A*, 115/120 for an A, 100 for a B, 75/80 for a C

Also what did you get for the question which I think you had to use the cosine rule for and how did you do it-don't think I did well on this one.

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#18

Also what did you get for the question which I think you had to use the cosine rule for and how did you do it-don't think I did well on this one.,

It was 1/2 ab sinc. Then you used the sine rule

It was 1/2 ab sinc. Then you used the sine rule

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(Original post by

Also what did you get for the question which I think you had to use the cosine rule for and how did you do it-don't think I did well on this one.,

It was 1/2 ab sinc. Then you used the sine rule

**JWKLA**)Also what did you get for the question which I think you had to use the cosine rule for and how did you do it-don't think I did well on this one.,

It was 1/2 ab sinc. Then you used the sine rule

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