20Emily1998
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#1
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How's everyone feeling about the further pure 1 tomorrow? Any predictions of particular questions?
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20Emily1998
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#2
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(Original post by wildilwh09)
I can easily predict the paper, like usual, will be a massive pile of masturbation. Absolute horse ****e.
Good luck anyway, but I get where you're coming from its usually too hard!
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claudia_19
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#3
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I think they might do a linear laws question... and i bet its going to be harder than last years... which was seriously challenging!
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masterchef97
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#4
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#4
Anyone know what alpha^4 + beta^4 is??
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J-To-The-Era-Wig
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#5
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(Original post by masterchef97)
Anyone know what alpha^4 + beta^4 is??
Pretty sure it's the expanded alpha^2+beta^2 all squared
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joef1337
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#6
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My answers' other than show that questions:

1) a) a+b = -3, ab = 7/2
b) 4x^2 + 45 = 0
c) a^2 = 1 + 3/2 sqrt(5) i, b^2 = 1 - 3/2 sqrt(5) i
2) a) Undefined at one limit of integration
b) Does not have a finite value
3) a) 2-11i
b) i) q=20 (z^3-11z+20=0)
ii) z^2- 4z + 5
iii) z = -4
4) a) x = {-5 + 120n, 35 + 120n}
b) 235
5) a) c=4, d=-1
b) i) -16I
ii) enlargement scale factor 2, rotation 45 degrees clockwise
iii) Fromleft to right, top to bottom: [[65536sqrt(2), 65536sqrt(2)], [-65536sqrt(2), 65536sqrt(2)]]
6) a) Hyperbola crossing (3,0) and (-3,0)
b) y = 4/3 x + 4, y = -4/3 x -4
7) a) 39.60
b) n(n+1)(2n+3)
c) i) 2/3 r
ii) k = 39
8) a) y = 1
b) (1, -1/2) and (-3, 3/2)

Not sure if they're right, feel free to make corrections.

Edit: what happened to my indentation?
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HarunH1
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#7
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#7
(Original post by joef1337)
My answers' other than show that questions:

1) a) a+b = -3, ab = 7/2
b) 4x^2 + 45 = 0
c) a^2 = 1 + 3/2 sqrt(5) i, b^2 = 1 - 3/2 sqrt(5) i
2) a) Undefined at one limit of integration
b) Does not have a finite value
3) a) 2-11i
b) i) q=20 (z^3-11z+20=0)
ii) z^2- 4z + 5
iii) z = -4
4) a) x = {-5 + 120n, 35 + 120n}
b) 235
5) a) c=4, d=-1
b) i) -16I
ii) enlargement scale factor 2, rotation 45 degrees clockwise
iii) Fromleft to right, top to bottom: [[65536sqrt(2), 65536sqrt(2)], [-65536sqrt(2), 65536sqrt(2)]]
6) a) Hyperbola crossing (3,0) and (-3,0)
b) y = 4/3 x + 4, y = -4/3 x -4
7) a) 39.60
b) n(n+1)(2n+3)
c) i) 2/3 r
ii) k = 39
8) a) y = 1
b) (1, -1/2) and (-3, 3/2)

Not sure if they're right, feel free to make corrections.

Edit: what happened to my indentation?
for 4b I got 1 as you have to state the value of n, atleast that's what i thought
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JDMason
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#8
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#8
(Original post by HarunH1)
for 4b I got 1 as you have to state the value of n, atleast that's what i thought
n=2 anyway, but you are meant to give the value of the solution closest to 200. This is the value of x. If you have written the value of x down you will probably still get the marks.
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YoYoDude012
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#9
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#9
(Original post by joef1337)
My answers' other than show that questions:

1) a) a+b = -3, ab = 7/2
b) 4x^2 + 45 = 0
c) a^2 = 1 + 3/2 sqrt(5) i, b^2 = 1 - 3/2 sqrt(5) i
2) a) Undefined at one limit of integration
b) Does not have a finite value
3) a) 2-11i
b) i) q=20 (z^3-11z+20=0)
ii) z^2- 4z + 5
iii) z = -4
4) a) x = {-5 + 120n, 35 + 120n}
b) 235
5) a) c=4, d=-1
b) i) -16I
ii) enlargement scale factor 2, rotation 45 degrees clockwise
iii) Fromleft to right, top to bottom: [[65536sqrt(2), 65536sqrt(2)], [-65536sqrt(2), 65536sqrt(2)]]
6) a) Hyperbola crossing (3,0) and (-3,0)
b) y = 4/3 x + 4, y = -4/3 x -4
7) a) 39.60
b) n(n+1)(2n+3)
c) i) 2/3 r
ii) k = 39
8) a) y = 1
b) (1, -1/2) and (-3, 3/2)

Not sure if they're right, feel free to make corrections.

Edit: what happened to my indentation?
Shouldn't 3a) be 2+11i
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JDMason
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#10
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(Original post by YoYoDude012)
Shouldn't 3a) be 2+11i
I think it was (2+i)^3?

= 2^3 + 3(2^2)(i) +3(2)(i)^2 + i^3

=8+12i -6 -i

=2+11i

yeah, it should be 2+11i
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Zhaohuang
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#11
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Hi for Q 6, I got k as -3 since k is less than <0 and then I substitute x to x+3. How did you get 4 ?!
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harrylarge
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#12
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It's K=40 on 7)c)ii). As solving the cubic = 0 gave an answer of ~39.579...
So when K=39 the value of the sum to 60 was less than the 1060.. value.
I'm not 100% though
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Zhaohuang
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#13
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Yo . Remember at the counter . It's k+1. Although I got 39. I think k is 38
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20Emily1998
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#14
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#14
How did everyone work out the asymptote question? i got 3+/- 4/3x ???
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Zhaohuang
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#15
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#15
(Original post by 20Emily1998)
How did everyone work out the asymptote question? i got 3+/- 4/3x ???

Hey ! X should be x+3 . Since the change is towards the variable x . So replace x by x +3 that's what I think . Hope some one can correct me if I am wrong
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TheKian
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#16
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#16
(Original post by joef1337)
My answers' other than show that questions:

1) a) a+b = -3, ab = 7/2
b) 4x^2 + 45 = 0
c) a^2 = 1 + 3/2 sqrt(5) i, b^2 = 1 - 3/2 sqrt(5) i
2) a) Undefined at one limit of integration
b) Does not have a finite value
3) a) 2-11i
b) i) q=20 (z^3-11z+20=0)
ii) z^2- 4z + 5
iii) z = -4
4) a) x = {-5 + 120n, 35 + 120n}
b) 235
5) a) c=4, d=-1
b) i) -16I
ii) enlargement scale factor 2, rotation 45 degrees clockwise
iii) Fromleft to right, top to bottom: [[65536sqrt(2), 65536sqrt(2)], [-65536sqrt(2), 65536sqrt(2)]]
6) a) Hyperbola crossing (3,0) and (-3,0)
b) y = 4/3 x + 4, y = -4/3 x -4
7) a) 39.60
b) n(n+1)(2n+3)
c) i) 2/3 r
ii) k = 39
8) a) y = 1
b) (1, -1/2) and (-3, 3/2)

Not sure if they're right, feel free to make corrections.

Edit: what happened to my indentation?
My 1c was what you got but squared
3a was 2+11i
How did you do 3)b)ii)?
for 5b)iii) I got 256sqrt(2), did I need to square 256?

How did you even get K?

Could you do an unofficial mark scheme thread because most of these look good
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Zhaohuang
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#17
(Original post by TheKian)
My 1c was what you got but squared
3a was 2+11i
How did you do 3)b)ii)?
for 5b)iii) I got 256sqrt(2), did I need to square 256?

How did you even get K?

Could you do an unofficial mark scheme thread because most of these look good
I got the same as what that guy got . I can't remember how I did it , if you remember the question I will help you . And the question about k , if you can give me the informations from the previous parts then I can help you
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TheKian
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#18
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Does anyone what the series had to be less than?
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KirstyG_psbkj
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#19
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Did anyone else get k=41 for the series question? Trying to figure out what I did wrong
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crayolaguy
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#20
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(Original post by KirstyG_psbkj)
Did anyone else get k=41 for the series question? Trying to figure out what I did wrong
i got k=38
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