# AQA AS Statistics 3 9th June 2015 - After Exam

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#1
Hey everyone how did the exam go and what answers did you get.
I know the nature of the exam means it's hard to remember full answers but hopefully we can piece together some.
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6 years ago
#2
Hey can someone in this thread help me do this question, on the aqa exam board but may be on both
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6 years ago
#3
I messed up on the contingency table question (question 2) I got a t.s of 0.07 and a c.v of 6.6 the t.s just doesn't seem right to me?
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6 years ago
#4
(Original post by douglas merritte)
I just recalculated the T.S for that contingency table question for another thread, and got 21.367
i got around 9 for my test statistic, which equation did you use? i used the |o-e|-0.5)^2 divided by E
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#5
(Original post by em1ly123)
i got around 9 for my test statistic, which equation did you use? i used the |o-e|-0.5)^2 divided by E
Yeah me to 9.29
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6 years ago
#6
(Original post by douglas merritte)
Oh man, maybe I got it wrong! Do you remember if there was a total of 65 people interviewed, is that right?
yeah 65 is ringing a bell in my head
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6 years ago
#7
(Original post by JamestheYorks)
Yeah me to 9.29
just checked my calculator because left it in there haha, 9.2961 is what i got
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6 years ago
#8
After doing |o-e|-0.5 did anyone get 0.54^2 for all 4? I had a total 65 so I'm hoping I didn't drop too many marks
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6 years ago
#9
Here are the answers I got guys, I will give the t.s and c.v:
1. 0.809>0.6581 --> reject H0
2. 9.30>6.635 --> reject H0
3. Tmin=21, 18>11 --> accept H0
4. r=0.767, r=-0.544, c.v=+-0.6833 so reject H0 for the 1st, accept H0 for the 2nd, sign test: 0.50>10% --> accept H0
5. 12.8>11.345 --> reject H0
6. 9<13 --> reject H0, 13>11 --> accept H0
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6 years ago
#10
(Original post by stelios98)
Here are the answers I got guys, I will give the t.s and c.v:
1. 0.809>0.6581 --> reject H0
2. 9.30>6.635 --> reject H0
3. Tmin=21, 18>11 --> accept H0
4. r=0.767, r=-0.544, c.v=+-0.6833 so reject H0 for the 1st, accept H0 for the 2nd, sign test: 0.50>10% --> accept H0
5. 12.8>11.345 --> reject H0
6. 9<13 --> reject H0, 13>11 --> accept H0
Yeah that's pretty much what I got expect my t.s was wrong for question two and so my conclusion was wrong. Hopefully I've only dropped around 2 marks
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#11
(Original post by stelios98)
Here are the answers I got guys, I will give the t.s and c.v:
1. 0.809>0.6581 --> reject H0
2. 9.30>6.635 --> reject H0
3. Tmin=21, 18>11 --> accept H0
4. r=0.767, r=-0.544, c.v=+-0.6833 so reject H0 for the 1st, accept H0 for the 2nd, sign test: 0.50>10% --> accept H0
5. 12.8>11.345 --> reject H0
6. 9<13 --> reject H0, 13>11 --> accept H0
With a couple of slight rounding differences that's exactly what i got
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6 years ago
#12
My answers - don't know if correct:1) a) r=0.809 b) PMCC, Reject Ho CV=0.6581 c) No girls included or no unhealthy included2) a) Contingency Yates, TS=9.3 CV=6.635, Reject Ho3) a) Min =21b) Ua=18 (also TS) Ub=38, CV=11, Accept Ho4)a) i) rs=0.767 ii) rs=-0.544bi) 2 tailed CV= +/- 0.6833 Reject Hoii) Accept Hoc) TS=4 CR<=2 accept Ho5) a) Rank Totals 60.5 18.5 88 86H=12.8 cv=11.345 Rejec Ho6) a) T+=9(TS) T-=96 2 tailed cv=13 9<13 reject Hob) T+=13(TS) T-=42 1 tailed cv=11 13>11 accept Ho
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