The Student Room Group

Reply 1

Hint: how would you integrate lnx?

Reply 2

Ooh, good thinking. :smile: Thanks.

Edit: so just to check (someone confirm please?), y = x arsinh x - ln sqrt(x^2+1) + c?

Reply 3

That is correct, darth.

generalebriety: x is not the derivative of sqrt(1 + x^2), you didn't apply the chain rule properly :tongue:

Reply 4

Speleo
That is correct, darth.

generalebriety: x is not the derivative of sqrt(1 + x^2), you didn't apply the chain rule properly :tongue:

I didn't apply the chain rule at all. :confused:

dy/dx = arsinh x
Integrating by parts,
u = arsinh x, u' = 1/sqrt(x^2 + 1)
v' = 1, v = x

y = x arsinh x - INT x/sqrt(x^2 + 1) dx
Let w^2 = x^2 + 1; then w dw = x dx.
y = x arsinh x - INT w/w^2 dw
= x arsinh x - INT 1/w dw
= x arsinh x - ln w + c
= x arsinh x - ln sqrt(x^2 + 1) + c.

What have I done wrong?


Edit: ignore me, found it. Thanks for the help. :smile:

Reply 5

I assumed that you'd ended up with INT x/sqrt(1+x^2) dx and said that d/dx sqrt(1+x^2) = 1/2 * 2x and ignored the sqrt(1+x^2)^(-1/2).

Reply 6

I think the most likely error was that, put w^2 on the bottom when in actual fact its w.

Reply 7

insparato
I think the most likely error was that, put w^2 on the bottom when in actual fact its w.

Well, thank you for your input into the situation, insparato. :p:

Reply 8

I made that error myself hey im not trying to sound superior here believe me im a far worst mathematician.

Reply 9

I think the most likely error was that, put w^2 on the bottom when in actual fact its w.

Well that is obvious now he has posted his method :tongue:
I was explaining my post after the incorrect answer and before the working.

Reply 10

insparato
I made that error myself hey im not trying to sound superior here believe me im a far worst mathematician.

Whether that's true or not, it doesn't stop you taking the piss from time to time. :p: Keeps me on my toes, though. :biggrin:

If anyone's interested, that question was taken from STEP I 1992 Q2.

Reply 11

Oh right that can happen.

Reply 12

generalebriety
Whether that's true or not, it doesn't stop you taking the piss from time to time. :p: Keeps me on my toes, though. :biggrin:

If anyone's interested, that question was taken from STEP I 1992 Q2.


:eek: wasnt trying to take the piss this time honest. My post was full of sincerity and no piss taking intentions.

Reply 13

insparato
:eek: wasnt trying to take the piss this time honest. My post was full of sincerity and no piss taking intentions.

Fair enough, sorry. :biggrin:

Reply 14

Not a problem :p:. (Interesting STEP question though).

Reply 15

Another integration question I can't do (not hyperbolic, but can't be bothered to make another thread): INT 1/(3cosx + 4sinx) dx. Any ideas? I've tried dividing top and bottom by cosx but that doesn't help, I've tried every single substitution I know... bah. :p:

Reply 16

Rsin(x+a) = Rsinxcosa + Rcosxsina

sina = 3

cosa = 4

tana = 3/4

a = 36.9

R = 5

5sin(x+36.9)

Reply 17

Oof. I knew that. :confused: Thanks. :smile:

Reply 18

darth_vader05
:eek: i've forgotten how to do that!:s-smilie:

So had I. :confused:

Reply 19

:smile: no problem.

C3 comes in handy :p:.