Following a flood 120 tins were recovered from Dharmesh's corner shop. Of the tins 50 contained pet food, 20 contained peas, 35 contained beans and 15 contained soup.
a) Dharmesh selects three tins at random (without replacement). Find the probability that one contains pet food, one contains peas and one contains beans. (answer = 0.125)
b) Find the probability that Dharmesh will have to open more than two tins before she finds one which does not contain pet food. (answer = 0.172)
They seem easy but somehow I keep on getting the wrong answers My Stats exam is tomorrow so I'm really starting to panic!
D and C go to the cinema. Probability that D buys popcorn is 0.4. Probability that C buys popcorn is 0.7 if D buys and 0.35 if D doesn't. They are joined by S. Probability that S buys popcorn is 0.55 if both D and C buy popcorn, and 0.25 when exactly one of D and C buys popcorn.
Find the probability that C and S buys popcorn but D doesn't.
I tried doing this and did 0.6 x 0.35 x 0.25 = 0.0525, but apparently the answer is 0.105....?