Oxbridge Maths Interview questions/advice.
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Original post by goodies
After looking at these I really know im not oxbridge material lmao 
same lol
Original post by ProtoxylicBut that's using FP2. I'm sure there's probably a way with comparing coefficients with FP1 knowledge.
Spoiler
I^i doesn't just have 1 value, consider the periodicity of sin and cos
Original post by Gome44
I^i doesn't just have 1 value, consider the periodicity of sin and cos
Obviously were are looking at the principal value.
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Original post by Gome44
I^i doesn't just have 1 value, consider the periodicity of sin and cos
The principal value would be 0.208
School boy error making my brain think that e^(-pi/2+2kpi) didn't produce different numbers lmao
(edited 8 years ago)
Original post by Protoxylic
Actually yes it does, 0.208....
If you are talking about adding multiples of 2pi to it's argument then that wouldn't give you a different numerical value. It's not like taking nth roots where you would have n roots all with different arguments
If you are talking about adding multiples of 2pi to it's argument then that wouldn't give you a different numerical value. It's not like taking nth roots where you would have n roots all with different arguments
No he is right. It takes lods of values, note that it would be e^-(pi/2+2kpi)
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For example e^ix=cosx+isinx
Let x=5pi/2
Then raise both sides to the ith power.
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Let x=5pi/2
Then raise both sides to the ith power.
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Original post by Protoxylic
Actually yes it does, 0.208....
If you are talking about adding multiples of 2pi to it's argument then that wouldn't give you a different numerical value. It's not like taking nth roots where you would have n roots all with different arguments
If you are talking about adding multiples of 2pi to it's argument then that wouldn't give you a different numerical value. It's not like taking nth roots where you would have n roots all with different arguments
?
i=e^i(5π/2) for example. i^i=e^-(5π/2) =/= 0.208
Original post by physicsmaths
But if you really wanted to impress the interviewer
Anyway, I doubt that question would come up as it's well known (I think it's on one of the trinity tests on mathshelper)
Original post by Gome44
But if you really wanted to impress the interviewer
Anyway, I doubt that question would come up as it's well known (I think it's on one of the trinity tests on mathshelper)
Anyway, I doubt that question would come up as it's well known (I think it's on one of the trinity tests on mathshelper)
Yes, I think so. It is good though. Where are you going this october?
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To see why we get multiple values:
First define
So
, for integer n.
So
So the multiple values come from the fact the argument is multi-valued. (Due to the periodicity of sine and cosine as Gome44 said)
First define
So
, for integer n.
So
So the multiple values come from the fact the argument is multi-valued. (Due to the periodicity of sine and cosine as Gome44 said)
(edited 8 years ago)
Original post by Gome44
?
i=e^i(5π/2) for example. i^i=e^-(5π/2) =/= 0.208
i=e^i(5π/2) for example. i^i=e^-(5π/2) =/= 0.208
Original post by physicsmaths
Yeah, I have no idea why I didn't think e^[-pi/2 +2npi] would be a different number, Jesus christ, school boy error
(edited 8 years ago)
Original post by physicsmaths
Oxford (grades permitting)
Nice, subject?
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Original post by physicsmaths
maths obviously
Original post by Gome44
But if you really wanted to impress the interviewer
Anyway, I doubt that question would come up as it's well known (I think it's on one of the trinity tests on mathshelper)
Anyway, I doubt that question would come up as it's well known (I think it's on one of the trinity tests on mathshelper)
i had a very similar question come up in my interview
Original post by TeeEm
maths obviously
Could be physics or engineering....
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Original post by MathMeister
true dat?
what language is this?
Original post by TeeEm
true dat?
what language is this?
what language is this?
Engrish, innit?
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