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Another maths question watch

1. Ok - can someone look at the following question for me please?

For question 7, are the ans to part

a) -4/5

b) y - (4/√2) = -4/5(x - 5/√2)

c) (10/√2 , 0)

d) can someone help me how to do this question?

Thanks
2. (Original post by Silly Sally)
Ok - can someone look at the following question for me please?

For question 7, are the ans to part

a) -4/5

b) y - (4/√2) = -4/5(x - 5/√2)

c) (10/√2 , 0)

d) can someone help me how to do this question?

Thanks
weird what are those 2 equations for?
3. Integrate the equation of the straight line, where the limits are the x-coordinates of P and R. Then integrate the equation of the curve (which should be made into Cartesian form) where the limits are the x-coordinates of P and the x-intercept. Deduct the first result from the second.
4. (Original post by Silly Sally)
Ok - can someone look at the following question for me please?

For question 7, are the ans to part

a) -4/5

b) y - (4/√2) = -4/5(x - 5/√2)

c) (10/√2 , 0)

d) can someone help me how to do this question?

Thanks
1) Is correct -4/5

I'm doing the rest now............be back in a minute.....
5. (Original post by Silly Sally)
Ok - can someone look at the following question for me please?

For question 7, are the ans to part

a) -4/5

b) y - (4/√2) = -4/5(x - 5/√2)

c) (10/√2 , 0)

d) can someone help me how to do this question?

Thanks
2) 5y=20√2-4x
6. dx/[email protected] = [email protected]
dy/[email protected] = [email protected]

dy/dx = [email protected]/[email protected]

@ = pi/4

4/root2/-5/root2 =- 4/5

y - (4/root2) = -4/5(x - 5/root2
5y -20/root2 = -4x + 20/root2
5y +4x -40/root2

c) y = 0

4x = 40/root2
x = 10/root2

doing d now
7. (Original post by Silly Sally)
Ok - can someone look at the following question for me please?

For question 7, are the ans to part

a) -4/5

b) y - (4/√2) = -4/5(x - 5/√2)

c) (10/√2 , 0)

d) can someone help me how to do this question?

Thanks
3) x=5√2, y=0
8. (Original post by imasillynarb)
dx/[email protected] = [email protected]
dy/[email protected] = [email protected]

dy/dx = [email protected]/[email protected]

@ = pi/4

4/root2/-5/root2 =- 4/5

y - (4/root2) = -4/5(x - 5/root2
5y -20/root2 = -4x + 20/root2
5y +4x -40/root2

c) y = 0

4x = 40/root2
x = 10/root2

doing d now
{ [40/root2 -4x]/2 between 10root2 and 5/root2

= [40x/2root2 - x^2]
= [200-200] - 50
= -50

and err im slightly stuck now
9. I have the cartesian equation as

16x^2+25y^2=400
10. (Original post by imasillynarb)
{ [40/root2 -4x]/2 between 10root2 and 5/root2

= [40x/2root2 - x^2]
= [200-200] - 50
= -50

and err im slightly stuck now
{ y dx

= { [email protected] dx

dx = [email protected] [email protected]

= { -20sin^[email protected] [email protected]
between 5 and 5/root2

= { -20([email protected]/2) [email protected]
{ -10+ [email protected] [email protected]

= [email protected] - [email protected] between pi/4 and pi/2

= [-10pi/4 - 5] - [-5pi -5]
= 5pi/2

5pi/2 - -50 = 5pi/2 + 50
11. (Original post by imasillynarb)
{ [40/root2 -4x]/2 between 10root2 and 5/root2

= [40x/2root2 - x^2]
= [200-200] - 50
= -50

and err im slightly stuck now
d is a bit of a *****. Is there any way to integrate 16x^2+25y^2=400?
12. (Original post by imasillynarb)
{ y dx

= { [email protected] dx

dx = [email protected] [email protected]

= { -20sin^[email protected] [email protected]
between 5 and 5/root2

= { -20([email protected]/2) [email protected]
{ -10+ [email protected] [email protected]

= [email protected] - [email protected] between pi/4 and pi/2

= [-10pi/4 - 5] - [-5pi -5]
= 5pi/2

5pi/2 - -50 = 5pi/2 + 50
ehh?
13. (Original post by Bhaal85)
ehh?
Thats how you integrate it isnt it?
14. (Original post by imasillynarb)
Thats how you integrate it isnt it?
I'm not sure what you are doing, are you using integration by substitution?
15. (Original post by Bhaal85)
I'm not sure what you are doing, are you using integration by substitution?
A method of it, yes, Ill do it on mathtype to make it clearer, give me a minute..
16. A question, how is everyone getting those fancy math characters on screen like the root signs?
17. (Original post by Bhaal85)
A question, how is everyone getting those fancy math characters on screen like the root signs?
From the character map. If you want you could copy and paste the symbols from my sig so you have them to hand.
18. (Original post by XTinaA)
From the character map. If you want you could copy and paste the symbols from my sig so you have them to hand.
Character map, how or where do I get it?
19. (Original post by Bhaal85)
Character map, how or where do I get it?
Computer:

Start > Programs > Accessories > System Tools > Character Map.
20. (Original post by XTinaA)
Computer:

Start > Programs > Accessories > System Tools > Character Map.
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