Let the force by the wind on each block be
T.
Let
F1,F2 be the friction between the blocks and the friction between the lower block and the floor respectively.
The upper block is moving to the right at constant speed thus
F1 is acting towards the left and
F1=T. Hence
T=F1=μM1g⇒M1=μgF1The lower block is moving to the left at constant speed thus
F1 on this block is acting towards the right and
F2 is also acting towards the right. Hence:
F=F1+T+F2=2F1+F2⇒F=2F1+μ(M1+M2)g⇒F1=2F−μ(M1+M2)gSubstitute this into the above expression of
M1, we have:
M1=2μgF−μ(M1+M2)gRearrange to make
M1 the subject, we get:
M1=3μgF−3M2