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P3 Integration - Follow Up Question from Other Thread? watch

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    ok due to me editing the thread title but the thread list not actually updating it ive made another threrad (in fear nobody will check it)

    so following up from my other question im having this problem:



    I need to find the general solution of:

    dy/dx = x(y^2 +1) / (x-1)y



    But my final answer has a -1 in it where the back has +1 any ideas?
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    (Original post by Sang)
    ok due to me editing the thread title but the thread list not actually updating it ive made another threrad (in fear nobody will check it)

    so following up from my other question im having this problem:



    I need to find the general solution of:

    dy/dx = x(y^2 +1) / (x-1)y



    But my final answer has a -1 in it where the back has +1 any ideas?
    this is what i get,but i dont understand ur query:
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    need y in terms of x sorry..... this is where i have the problem
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    (Original post by Sang)
    need y in terms of x sorry..... this is where i have the problem
    i get y^2 = A.(e^x)(x-1) -1 , where A is a positive constant
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    answer claims


    y=-/+ (root) k(x-1)^2 e^2x + 1
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    (Original post by Sang)
    answer claims


    y=-/+ (root) k(x-1)^2 e^2x + 1
    I get

    y = -/+ sqrt( k(x-1)² . e^2x - 1

    -1 not +1 :confused:
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    yep thats what i thought must be error in answer, cant see how u can have the +1
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    It prob is an error
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    (Original post by IntegralAnomaly)
    this is what i get,but i dont understand ur query:
    u missed out the 1/2 I think.

    answer should be:

    (1/2)ln(y^2+1) = x + ln(x-1)
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    (Original post by ResidentEvil)
    u missed out the 1/2 I think.

    answer should be:

    (1/2)ln(y^2+1) = x + ln(x-1)
    oops.Well spotted.
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    (Original post by ResidentEvil)
    u missed out the 1/2 I think.

    answer should be:

    (1/2)ln(y^2+1) = x + ln(x-1)
    so that's why i was getting it wrong :rolleyes:
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    (Original post by mockel)
    so that's why i was getting it wrong :rolleyes:
    i hope im not to blame there
 
 
 

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