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P2 Functions questions! watch

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    The function P & Q are defined by:

    P:X -------> Ax+B

    Q:X -------> Cx+D

    Where A,B,C and D are constants, Guven that pq(x)=qp(x), show that:

    D(A-1) = B(c-1)


    I really got stuck on this one, dunno why, seems simple enough but i dunno...
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    Anyone??????
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    (Original post by KOH)
    The function P & Q are defined by:

    P:X -------> Ax+B

    Q:X -------> Cx+D

    Where A,B,C and D are constants, Guven that pq(x)=qp(x), show that:

    D(A-1) = B(c-1)


    I really got stuck on this one, dunno why, seems simple enough but i dunno...
    pq(x) = qp(x) therefore:

    A(Cx+D) + B = C(Ax+B) + D
    ACx+AD+B = ACx+BC+D
    AD-D=BC-B factorise to get:
    D(A-1)=B(C-1)
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    (Original post by Bhaal85)
    pq(x) = qp(x) therefore:

    A(Cx+D) + B = C(Ax+B) + D
    ACx+AD+B = ACx+BC+D
    AD-D=BC-B factorise to get:
    D(A-1)=B(C-1)

    Thnks
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    (Original post by KOH)
    Thnks
 
 
 
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