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Functional group isomers?
Hey!
I've been given the following equations: C5H10O and C4H8O2
For C5H10O (pentanal) I have:
pentan-2-one and pentan-3-one. Now I'm a little confused as to whether I also include 2-methylbutanal and 3-methylbutanal.
For C4H8O2 (butanoic acid) I'm really confused as to what I can do. Can I move the =O and the OH separately? Because surely there's quite a few possibilites there.
Thanks!
Just realised that this is in the Science forum rather than Chem sub-forum. Sorry mods
Move if necessary
I've been given the following equations: C5H10O and C4H8O2
For C5H10O (pentanal) I have:
pentan-2-one and pentan-3-one. Now I'm a little confused as to whether I also include 2-methylbutanal and 3-methylbutanal.
For C4H8O2 (butanoic acid) I'm really confused as to what I can do. Can I move the =O and the OH separately? Because surely there's quite a few possibilites there.
Thanks!
Just realised that this is in the Science forum rather than Chem sub-forum. Sorry mods
Move if necessary Reply 1
Couldxbe
Hey!
I've been given the following equations: C5H10O and C4H8O2
For C5H10O (pentanal) I have:
pentan-2-one and pentan-3-one. Now I'm a little confused as to whether I also include 2-methylbutanal and 3-methylbutanal.
Hey!
I've been given the following equations: C5H10O and C4H8O2
For C5H10O (pentanal) I have:
pentan-2-one and pentan-3-one. Now I'm a little confused as to whether I also include 2-methylbutanal and 3-methylbutanal.
Yes, 2-methylbutanal and 3-methylbutanal should be included.
Couldxbe
For C4H8O2 (butanoic acid) I'm really confused as to what I can do. Can I move the =O and the OH separately? Because surely there's quite a few possibilites there.
For C4H8O2 (butanoic acid) I'm really confused as to what I can do. Can I move the =O and the OH separately? Because surely there's quite a few possibilites there.
No, you shouldn't move the =OH and the -OH separately. -COOH should be united since it's the function group for this acid.
Hope this helps
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