for 2)
dy/dx = -8x+3x^2, so plug in 1,-1, to find gradient of tangent.
find equation of the line of the tangent, using change iny/change in x = gradient
(gradient known, and the point 1,-1 value used) i.e. y+1/x-1 = gradient
then use this equation and solve it simultaneously with the equation of the curve to find the coordinates of where they intersect.
put the values of these coordinates into the dy/dx equation and find equation of this line.