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impossible GCSE circle theorem question
could a genius please work this out.......pretty please!
ps. please excuse the terrible diagram
....
it should say:
ABCD is a cyclic quadrilateral
PAQ is a tangent to the circle at A
BC = CD
AD is parralel to BC
angle BAQ = 32 degrees
find the size of angle BAD
ps. please excuse the terrible diagram
.... it should say:
ABCD is a cyclic quadrilateral
PAQ is a tangent to the circle at A
BC = CD
AD is parralel to BC
angle BAQ = 32 degrees
find the size of angle BAD
Reply 1
Saf!
OP
anyone?
Reply 2
14
Saf!
could a genius please work this out.......pretty please!
ps. please excuse the terrible diagram ....
it should say:
ABCD is a cyclic quadrilateral
PAQ is a tangent to the circle at A
BC = CD
AD is parralel to BC
angle BAQ = 32 degrees
find the size of angle BAD
ps. please excuse the terrible diagram
.... it should say:
ABCD is a cyclic quadrilateral
PAQ is a tangent to the circle at A
BC = CD
AD is parralel to BC
angle BAQ = 32 degrees
find the size of angle BAD
do you know what the answer is.....i got 64 degrees, but i could easily be wrong, since i've forgotten all these circle theoroms
Reply 3
I get 116 degrees. Is that right?
Allternate segment theorem to get <ADB and <ABD , and because it's an isoceles, 2x + y = 180
2 times 32 - 64 180 -64
<BAD = 116 degrees?
Allternate segment theorem to get <ADB and <ABD , and because it's an isoceles, 2x + y = 180
2 times 32 - 64 180 -64
<BAD = 116 degrees?
Reply 4
i did tht paper in exam conditions in class and i got 64 degrees which was wrong but i dont know the right answer! anybody know the right answer??
xxx
xxx
Reply 5
hey PPl
I just tried that Q and a mate of mine did aswell. We both got BAD = 64
Are you sure thats wrong ? Could your teacher of marked it badly ?
Chris
I just tried that Q and a mate of mine did aswell. We both got BAD = 64
Are you sure thats wrong ? Could your teacher of marked it badly ?
Chris
Reply 6
14
this is how i did it...
angle BDA = 32 , because of angle in opposite segment rule
angle DBC = 32 , because of alternate ('Z') angles
angle BDC = 32 , because triangle BCD is isoceles
angle BCD = 116 , because angles in a triangle add up to 180
therefore angle BAD = 64 , because opposite angles in a cyclic quad. add up to 180.
angle BDA = 32 , because of angle in opposite segment rule
angle DBC = 32 , because of alternate ('Z') angles
angle BDC = 32 , because triangle BCD is isoceles
angle BCD = 116 , because angles in a triangle add up to 180
therefore angle BAD = 64 , because opposite angles in a cyclic quad. add up to 180.
Reply 7
the answer is 64.
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