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could a genius please work this out.......pretty please!

ps. please excuse the terrible diagram ....

it should say:

ABCD is a cyclic quadrilateral

PAQ is a tangent to the circle at A

BC = CD

AD is parralel to BC

angle BAQ = 32 degrees

find the size of angle BAD

ps. please excuse the terrible diagram ....

it should say:

ABCD is a cyclic quadrilateral

PAQ is a tangent to the circle at A

BC = CD

AD is parralel to BC

angle BAQ = 32 degrees

find the size of angle BAD

Saf!

could a genius please work this out.......pretty please!

ps. please excuse the terrible diagram ....

it should say:

ABCD is a cyclic quadrilateral

PAQ is a tangent to the circle at A

BC = CD

AD is parralel to BC

angle BAQ = 32 degrees

find the size of angle BAD

ps. please excuse the terrible diagram ....

it should say:

ABCD is a cyclic quadrilateral

PAQ is a tangent to the circle at A

BC = CD

AD is parralel to BC

angle BAQ = 32 degrees

find the size of angle BAD

do you know what the answer is.....i got 64 degrees, but i could easily be wrong, since i've forgotten all these circle theoroms

this is how i did it...

angle BDA = 32 , because of angle in opposite segment rule

angle DBC = 32 , because of alternate ('Z') angles

angle BDC = 32 , because triangle BCD is isoceles

angle BCD = 116 , because angles in a triangle add up to 180

therefore angle BAD = 64 , because opposite angles in a cyclic quad. add up to 180.

angle BDA = 32 , because of angle in opposite segment rule

angle DBC = 32 , because of alternate ('Z') angles

angle BDC = 32 , because triangle BCD is isoceles

angle BCD = 116 , because angles in a triangle add up to 180

therefore angle BAD = 64 , because opposite angles in a cyclic quad. add up to 180.

the answer is 64.

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