# Simultaneous equation help!!

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Can anyone tell me how to solve this using substitution method?

y-x/2=1

x/3+2y=10

y-x/2=1

x/3+2y=10

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#2

(Original post by

Can anyone tell me how to solve this using substitution method?

y-x/2=1

x/3+2y=10

**neza99**)Can anyone tell me how to solve this using substitution method?

y-x/2=1

x/3+2y=10

-x/2+y=1

X/3+2y=10

And then Multiply the first equation by two so the first equation becomes -x+2y=2 and then subtract the two equations from each other,,.

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(Original post by

You could rearrange the equations like this..

-x/2+y=1

X/3+2y=10

And then Multiply the first equation by two so the first equation becomes -x+2y=2 and then subtract the two equations from each other,,.

**GalGirl101**)You could rearrange the equations like this..

-x/2+y=1

X/3+2y=10

And then Multiply the first equation by two so the first equation becomes -x+2y=2 and then subtract the two equations from each other,,.

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#4

**neza99**)

Can anyone tell me how to solve this using substitution method?

y-x/2=1

x/3+2y=10

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#5

Multiply the first equation by 2 to get 2y - x = 2. Rearrange to get x = 2y - 2.

Multiply the second equation by 3 to get x + 6y = 30. Substitute x into the second equation to get 8y - 2 = 30.

Therefore, y = 4 and further solving results in x = 6.

Multiply the second equation by 3 to get x + 6y = 30. Substitute x into the second equation to get 8y - 2 = 30.

Therefore, y = 4 and further solving results in x = 6.

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(Original post by

GalGirl101's method is the most efficient for solving these. However, to solve them by substitution, you need to rearrange one so that x or y is the subject and use this to solve the other equation by substituting it in so that you have an equation with only x or y. The first is easier to rearrange so should start there

**DodoManiac**)GalGirl101's method is the most efficient for solving these. However, to solve them by substitution, you need to rearrange one so that x or y is the subject and use this to solve the other equation by substituting it in so that you have an equation with only x or y. The first is easier to rearrange so should start there

y=1+x/2 i made y the subject

x/3+2y=10

so x/3+2(1+x/2)=10

x/3+2+x=10

2x/3=8 i minused 2 from both sides.

2x=24

x=12 i did this but it didn't work :/

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#7

(Original post by

i think i did that, i show you

y=1+x/2 i made y the subject

x/3+2y=10

so x/3+2(1+x/2)=10

x/3+2+x=10

2x/3=8 i minused 2 from both sides.

2x=24

x=12 i did this but it didn't work :/

**neza99**)i think i did that, i show you

y=1+x/2 i made y the subject

x/3+2y=10

so x/3+2(1+x/2)=10

x/3+2+x=10

2x/3=8 i minused 2 from both sides.

2x=24

x=12 i did this but it didn't work :/

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(Original post by

Right method, just an arithmetic slip. What's 1/3 + 1?

**DodoManiac**)Right method, just an arithmetic slip. What's 1/3 + 1?

1 1/3? i'm not really good in this bit

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#9

(Original post by

1 1/3? i'm not really good in this bit

**neza99**)1 1/3? i'm not really good in this bit

Think of it as 1/3 + 3/3 if that helps

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(Original post by

Yeah that's right, or as a single fraction? You said x/3 + x = 2x/3

Think of it as 1/3 + 3/3 if that helps

**DodoManiac**)Yeah that's right, or as a single fraction? You said x/3 + x = 2x/3

Think of it as 1/3 + 3/3 if that helps

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**DodoManiac**)

Yeah that's right, or as a single fraction? You said x/3 + x = 2x/3

Think of it as 1/3 + 3/3 if that helps

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#12

(Original post by

OMG, thank you very much it worked now! may i ask if you know what level question is this?

**neza99**)OMG, thank you very much it worked now! may i ask if you know what level question is this?

I'm not too sure what level question it is to be honest but would guess at higher level GCSE/starter question on a C1 paper (AS).

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(Original post by

Great! No problem, happy to help

I'm not too sure what level question it is to be honest but would guess at higher level GCSE/starter question on a C1 paper (AS).

**DodoManiac**)Great! No problem, happy to help

I'm not too sure what level question it is to be honest but would guess at higher level GCSE/starter question on a C1 paper (AS).

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#14

**neza99**)

Can anyone tell me how to solve this using substitution method?

y-x/2=1

x/3+2y=10

Then, put some though into the equation and think how to get x without the divisor, if x is divided by 2, what would you multiply to it to make it just x (1x).

Remember you have to multiply the entire equation by that value and not only x.

Do this for the second equation and then subtract both of the equations to get y on it's own = to something.

Solve for y and then substitute y into the equation to solve for x.

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