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FP2 Differential Equation

http://i.imgur.com/QzjkXLi.png

Need help with the substitution bit on question 1.
Original post by Nirm
http://i.imgur.com/QzjkXLi.png

Need help with the substitution bit on question 1.


What have you done so far? If you're having problems getting started, try differentiating z=sinxz=sinx implicitly with respect to y and then rearrange to get an expression for dydx\frac{dy}{dx}.

With these questions, it's always a good idea to try to find expressions for the differential parts and then slot them into the equation. For instance, in the equation they've given us, we've got dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2} so you should be immediately thinking, "how do I get an expression with dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2}?". There's no yy term in the substitution so a good first step would be differentiating with respect to yy.
(edited 8 years ago)
Reply 2
Original post by Nirm
http://i.imgur.com/QzjkXLi.png

Need help with the substitution bit on question 1.


the standard method when you start solving ODEs and they give you a substitution is to

find expressions for dy/dx and d2y/dx2 by suitably differentiating your substitution.
Reply 3
Original post by Plagioclase
What have you done so far? If you're having problems getting started, try differentiating z=sinxz=sinx implicitly with respect to y and then rearrange to get an expression for dydx\frac{dy}{dx}.

With these questions, it's always a good idea to try to find expressions for the differential parts and then slot them into the equation. For instance, in the equation they've given us, we've got dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2} so you should be immediately thinking, "how do I get an expression with dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2}?". There's no yy term in the substitution so a good first step would be differentiating with respect to yy.


Original post by TeeEm
the standard method when you start solving ODEs and they give you a substitution is to

find expressions for dy/dx and d2y/dx2 by suitably differentiating your substitution.


I keep getting stuck at the d^2y/dx^2. I get dy/dx=dy/dz*dz/dx. The confusing bit is that when trying to get the second derivative, should i leave the dz/dx in dy/dx as it is or substitute it for cosx?
Original post by Nirm
I keep getting stuck at the d^2y/dx^2. I get dy/dx=dy/dz*dz/dx. The confusing bit is that when trying to get the second derivative, should i leave the dz/dx in dy/dx as it is or substitute it for cosx?


It'll probably make your life easier if you write it as dy/dx=cosx*dy/dz and then differentiate. You'll find it works out quite neatly. There are no dz/dx terms anywhere in the question but there is cos x, so that's a possible hint that you should exchange the former for the latter.
Reply 5
Original post by Nirm
I keep getting stuck at the d^2y/dx^2. I get dy/dx=dy/dz*dz/dx. The confusing bit is that when trying to get the second derivative, should i leave the dz/dx in dy/dx as it is or substitute it for cosx?


look at a similar question (Q10) in this link

http://madasmaths.com/archive/maths_booklets/further_topics/integration/2nd_order_differential_equations_substitutions.pdf
Reply 6


Thank you very much for the link. It's the exact same question(well the first half anyway)! Made everything really clear.
Reply 7
Original post by Plagioclase
It'll probably make your life easier if you write it as dy/dx=cosx*dy/dz and then differentiate. You'll find it works out quite neatly. There are no dz/dx terms anywhere in the question but there is cos x, so that's a possible hint that you should exchange the former for the latter.


Yep it did :colondollar:
Reply 8
Original post by Nirm
Thank you very much for the link. It's the exact same question(well the first half anyway)! Made everything really clear.


no worries

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