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    Heres the question:

    Solve:

    3x/(x-2)(x+4) = 1/3

    values of x = ..... or x = .....

    Please help asap got exams in a hr or so. thanks.
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    (Original post by jasons61)
    Heres the question:

    Solve:

    3x/(x-2)(x+4) = 1/3

    values of x = ..... or x = .....

    Please help asap got exams in a hr or so. thanks.
    multiply the whole equation through by 3(x-2)(x+4) to get:

    9x = x^2 + 2x - 8

    solve that equation (x^2 - 7x - 8) = 0

    which factorises into (x+1)(x-8)=0

    so x = -1, or x = 8.
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    wow thanks alot much appreciated cant belive i didnt know that!
 
 
 
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