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    Please can someone explain to me how to solve the following equation:
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    (Original post by Pixelfairy #1)
    Please can someone explain to me how to solve the following equation:
    asssuming that k is a constant
    just expand the (1-2x)(1-4x) and integrate...
    you dont have to add the k
    leave it out when integrating
    after integrating,put the k back in
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    (Original post by MalaysianDude)
    asssuming that k is a constant
    just expand the (1-2x)(1-4x) and integrate...
    you dont have to add the k
    leave it out when integrating
    after integrating,put the k back in
    Did you notice that the LHS is dy/dt and not dy/dx?

    Pixelfairy, is x a function of t? Maybe you can use dy/dx = dy/dt * dt/dx and then integrate the RHS wrt x (not sure though).
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    (Original post by MalaysianDude)
    asssuming that k is a constant
    just expand the (1-2x)(1-4x) and integrate...
    you dont have to add the k
    leave it out when integrating
    after integrating,put the k back in
    lol that makes sense... but I tried to take the xs over to the other side and ended up with 1/the quadratic

    Thanks... I'm having a bad P3 day today
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    (Original post by Pixelfairy #1)
    Please can someone explain to me how to solve the following equation:

    dy/dx = k(1 - 2x)(1 - 4x)

    Put all x's onto the right hand side and multiply out brackets.
    dy/k = 1 - 6x + 8x^2

    Then integrate:
    {1/k.dy = {1 - 6x + 8x^2.dx

    Answer = 1/k.y = x - 3x^2 + 8x^3/3 + C
 
 
 
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