# Calculate the number of moles of ... In 11g of carbon dioxide

Watch
#1
of C atoms and of O atoms. please can you explain too.
0
5 years ago
#2
(Original post by hedgehoghog)
of C atoms and of O atoms. please can you explain too.
I dropped chemistry after GCSE, so someone else may be better placed to answer this, but...

Mass = Mr x Moles where Mass = 11, Mr = 12 + 16 + 16 = 44.

Hence, Moles = 11/44 = 0.25 moles of CO2.

Thus, we have 0.25 x 1 = 0.25 moles of carbon and 0.25 x 2 = 0.50 moles of oxygen.

Hopefully that helps (and hopefully I'm correct).
1
5 years ago
#3
(Original post by SH0405)
I dropped chemistry after GCSE, so someone else may be better placed to answer this, but...

Mass = Mr x Moles where Mass = 11, Mr = 12 + 16 + 16 = 44.

Hence, Moles = 11/44 = 0.25 moles of CO2.

Thus, we have 0.25 x 1 = 0.25 moles of carbon and 0.25 x 2 = 0.50 moles of oxygen.

Hopefully that helps (and hopefully I'm correct).
Correct
1
#4
(Original post by SH0405)
I dropped chemistry after GCSE, so someone else may be better placed to answer this, but...

Mass = Mr x Moles where Mass = 11, Mr = 12 + 16 + 16 = 44.

Hence, Moles = 11/44 = 0.25 moles of CO2.

Thus, we have 0.25 x 1 = 0.25 moles of carbon and 0.25 x 2 = 0.50 moles of oxygen.

Hopefully that helps (and hopefully I'm correct).
1
5 years ago
#5
(Original post by hedgehoghog)
No worries.
0
2 years ago
#6
(Original post by SubwayLover1)
Correct
can you tell me why its correct? like my teacher didnt explain it and im confused now
0
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

#### Current uni students - are you thinking of dropping out of university?

Yes, I'm seriously considering dropping out (129)
14.74%
I'm not sure (40)
4.57%
No, I'm going to stick it out for now (264)
30.17%
I have already dropped out (22)
2.51%
I'm not a current university student (420)
48%