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    (Original post by TheWolf)
    yea it was worse during the exams tho! we had to wear our school uniforms too which was 101.3% gay :eek: anyways better do some revision cya!
    Don't have uniforms, wouldn't know Have fun with the revision!
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    (Original post by Ellie4)
    I'm doing ASs, but don't worry, last years maths paper was really hard, so the grade boundaries were really low - 40% for a C or something!
    What u talking about I took lst years gcse edexcel maths and found it really easy i had an hour left in one paper just to twiddle my thumbs.
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    (Original post by meawinner)
    What u talking about I took lst years gcse edexcel maths and found it really easy i had an hour left in one paper just to twiddle my thumbs.
    Well you must have got a very high A* then, congratulations.
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    I got the 1's u guys r talking bout i.e the car and probability, but they were v. tough. My whole year found it tough, so i wouldn't worry. Please ask 4 any solutions.
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    (Original post by leggemeister)
    I got the 1's u guys r talking bout i.e the car and probability, but they were v. tough. My whole year found it tough, so i wouldn't worry. Please ask 4 any solutions.
    Did you get the same answer as me? (see earlier post).
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    i got 1600 and 0.5 too but i didn't do it from the graph...oops. o well. i couldnt do the tangent congruent triangles question at all but i found the sin things quite easy i got y=sinx +1 and y=2sinx. what did you put for the circle toughing all the edges question?
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    what did everyone get for the percentage surd square question. i think i got sumthin like 83%
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    (Original post by tango1)
    what did everyone get for the percentage surd square question. i think i got sumthin like 83%
    It was 83.33333 %
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    (Original post by samdavyson)
    It was 83.33333 %
    u reckon they'll give me it as 83 cos they didnt ay nethin bout decimal places
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    thats good i got 83.3 recurring i think. Yeh i had no idea about the circle and the vertex.

    Ure answers looks good sam, I got the first three parts right. Found the others hard but i think i picked a few marks, i was on the right track
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    (Original post by tango1)
    u reckon they'll give me it as 83 cos they didnt ay nethin bout decimal places
    Well I am sure that will get 5/5.
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    (Original post by andy_)
    thats good i got 83.3 recurring i think. Yeh i had no idea about the circle and the vertex.

    Ure answers looks good sam, I got the first three parts right. Found the others hard but i think i picked a few marks, i was on the right track
    for the circle touching all the vectors is a trignle question I said it was because a triangle in a semi circle is a right angled triange or something like that...

    Sam can you please post a solution for the surd probability one and explain how you work it out please?

    The paper was pretty tough though wasn't it?
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    so what did u think of the tangent question with the congruent triangles?
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    oh and how did you explain the transformations at the end?
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    (Original post by soapsuds)


    for the circle touching all the vectors is a trignle question I said it was because a triangle in a semi circle is a right angled triange or something like that...

    Sam can you please post a solution for the surd probability one and explain how you work it out please?

    The paper was pretty tough though wasn't it?
    I did Modular and my paper didn't have a surd probability question.
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    somebody's fone went off in our exam. rnt u supposed to get disqualified for that? none of the teachers did anything tho.
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    (Original post by samdavyson)
    I did Modular and my paper didn't have a surd probability question.
    Oops I meant the surd percentage one
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    do u remember how many marks the probability qs were each worth? cheers
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    (Original post by soapsuds)


    Oops I meant the surd percentage one
    Ok. You have a rectangle that is √20 + √5 by √8. A smaller rectangle size √5 by √2 was cut out of it.

    Percentage cut out = (√5 x √2) / [(√20 + √5)(√8)]

    = (√5 x √2) / [(√4√5 + √5)(√4√2)]

    = (√5 x √2) / [(2√5 + √5)(2√2)]

    = (√5 x √2) / [(3√5)(2√2)]

    = (√5 x √2) / [(6√5√2)]

    (The bits in red cancel)

    = 1/6

    Therefore 5/6 is left. This is 83.33%.
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    how'd ya remember all the questions? i'd forgot most of them wen i walked out the exam room.
 
 
 
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