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    Struggling with this question, can anyone help? "A family has four daughters: Molly, daisy, Rosie and Tilly. Daisy is six years older than Molly. Molly is four years younger than Tilly. Rosie is one year older than double Molly's age. The total of their ages is 51.
    By forming and solving an equation, find the age of each girl."
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    Use algebra and give Molly the value of x and work it out from there...
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    (Original post by Loyale)
    Use algebra and give Molly the value of x and work it out from there...
    I agree, algebra needs to be used here like mentioned above.
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    (Original post by Custardcream000)
    Struggling with this question, can anyone help? "A family has four daughters: Molly, daisy, Rosie and Tilly. Daisy is six years older than Molly. Molly is four years younger than Tilly. Rosie is one year older than double Molly's age. The total of their ages is 51.
    By forming and solving an equation, find the age of each girl."
    We know that:

    D=6+M
    M=T-4
    R=1+2M

    D+M+R+T=51

    Therefore:

    (6+M)+(T-4)+(1+2M)+T=51
    3+3M+2T=51
    3M+2T=48
    3(T-4)+2T=48
    3T-12+2T=48
    5T=60
    T=12

    Tillys age:
    T=12

    Molly's age:

    M=12-4
    M=8

    Rosie's age:

    R=1+2(8)
    R=17

    Daisy's age:
    D=6+8
    D=14




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    Make Molly's age m, the only unknown.

    Daisy is m+6
    Tilly is m+4
    Rosie is 2m +1

    m+m+6+m+4+2m+1=51
    5m=40
    m=40/5=8

    therefore:
    Molly is 8, Daisy is 14, Tilly is 12 and Rosie is 17 😃
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    Let x represent Mollie's age. Let d, r and t represent Daisy's, Rosie's and Tilly's age in that order.

    x = x
    d = x + 6
    r = 2x + 1
    t = x + 4

    Since we have all of their ages in terms of one variable, let's sum them up knowing that the sum is 51.

    x + x + 6 + 2x + 1 + x + 4 = 51
    5x + 11 = 51
    5x = 40
    x = 8

    Now we can substitute this value of x for all the equations we found earlier.

    x = 8
    d = 8 + 6 = 14
    r = 2(8) + 1 = 17
    t = 8 + 4 = 12

    So Mollie is 8 years old, Daisy is 14 years old, Rosie is 17 years old and Tilly is 12 years old.

    EDIT: Everyone else before me seems to have made mistakes... Just to double check my answers: 8 + 14 + 17 + 12 = 51
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    (Original post by kennethdcharles)
    Make Molly's age m, the only unknown.

    Daisy is m+6
    Tilly is m+4
    Rosie is 2m +1

    m+m+6+m+4+2m+1=51
    5m=40
    m=40/5=9

    therefore:
    Molly is 9, Daisy is 15, Tilly is 13 and Rosie is 19 😃
    You've made a mistake, 40/5 = 8, not 9.
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    L
    (Original post by Dingooose)
    You've made a mistake, 40/5 = 8, not 9.
    lol I corrected myself 😃
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    (Original post by pwnagee)
    We know that:

    D=6+M
    M=T-4
    R=1+2M

    D+M+R+T=51

    Therefore:

    (6+M)+(T-4)+(1+2M)+T=51
    3+3M+2T=51
    3M+2T=48
    3(T-4)+2T=48
    3T-12+2T=48
    5T=60
    T=12

    Tillys age:
    T=12

    Molly's age:

    M=12-4
    M=8

    Rosie's age:

    R=1+2(8)
    R=11

    Daisy's age:
    D=6+8
    D=14




    Posted from TSR Mobile
    molly is eight rosy is seventeen Tilly is twelve and daisy is fourteen
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    Thank you so much that was really helpful 🙃🙂
 
 
 

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