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    Solve 2x+ 3 = x/5
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    (Original post by Custardcream000)
    Solve 2x+ 3 = x/5
    Multiple through by 5 (to get rid of the fraction on the right).
    Then collect like terms (so x on one side).
    Then solve.
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    (Original post by Custardcream000)
    Solve 2x+ 3 = x/5

    times EVERYTHING on the left hand side by 5 to get rid of the fraction, so you get 10x + 15 = x , move xs on one side, you get 9x= -15, so x = -15/9
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    (Original post by ihatehannah)
    times EVERYTHING on the left hand side by 5 to get rid of the fraction, so you get 10x + 15 = x , move xs on one side, you get 9x= -15, so x = -15/9
    be careful not to give full working... you can be punished
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    2x+3 = x/5,
    x is divided by 5 on the right so, if you multiply both sides by 5 then, 10x+15 = x as 5 gets eliminated on the right.
    then you can bring the x on the right to left by subtracting both sides by x then you will get 9x+15 = 0.
    To make x as a subject, subtract both sides by 15 and you will get 9x = -15. Dividing both sides by 9 and you get x = -5/3, "I have simplified -15/9 by dividing it by common factor 3 so you get -5/3". I hope you understood the method, all you need to do is make x as the subject here
 
 
 

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