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    I often spend lots of time on pratice exam papers working out the areas enclosed by

    x=asint
    y=bcost

    no-one ever told me that the area of an ellipse with radii (r1) and (r2) = pi(r1)(r2). This sshould ssave so much time in P3 if it comess up.

    MB
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    (Original post by musicboy)
    I often spend lots of time on pratice exam papers working out the areas enclosed by

    x=asint
    y=bcost

    no-one ever told me that the area of an ellipse with radii (r1) and (r2) = pi(r1)(r2). This sshould ssave so much time in P3 if it comess up.

    MB
    you'll almost certainly be told to use integration to find the area, otherwise its too easy
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    (Original post by It'sPhil...)
    you'll almost certainly be told to use integration to find the area, otherwise its too easy
    damn!!! At least it is a good way to check my answer.

    MB
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    Oh yeah, and if they forget to write "by integration" then i'm using my method.

    MB
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    (Original post by musicboy)
    I often spend lots of time on pratice exam papers working out the areas enclosed by

    x=asint
    y=bcost

    no-one ever told me that the area of an ellipse with radii (r1) and (r2) = pi(r1)(r2). This sshould ssave so much time in P3 if it comess up.

    MB
    ooh! i didnt know that! Cheers.. yeah, like you said, good way of checking answer. :cool:
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    (Original post by musicboy)
    I often spend lots of time on pratice exam papers working out the areas enclosed by

    x=asint
    y=bcost

    no-one ever told me that the area of an ellipse with radii (r1) and (r2) = pi(r1)(r2). This sshould ssave so much time in P3 if it comess up.

    MB
    Ohhh didn't actually know that, does that mean that if we are given something like....

    x = 4cost
    y= 6sint

    Then the area would be given by (3)(2)pi??? :confused:
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    (Original post by Leekey)
    Ohhh didn't actually know that, does that mean that if we are given something like....

    x = 4cost
    y= 6sint

    Then the area would be given by (3)(2)pi??? :confused:
    wouldnt it be (4)(6)pi?
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    (Original post by kimoni)
    wouldnt it be (4)(6)pi?
    Ahh yes sorry, I typed out the equations and the proposed answer and then decided to change them for slightly more intersting numbers....*doh* :rolleyes:
 
 
 
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