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# Stats help!!:Permutations watch

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1. thanks for clicking depite the hellish title of the thread. ok, here goes...
q1) a coin is tossed 10 times, how may differant sequences are possible?

(i thought this would simply be 10P2 - but no, its 2^10 - why???????)

q2) (same theme) 8 cards are dealt from a pack of 52 cards, with replacement, how may differant sequances are possible?

(again its not 52P8 - its 52^8 - *cries*)

my question basically is what makes these situations unsuitable to use permutations???
2. the first might be true if you were using a 10 sided coin

however a coin is only two sided, so in each case you get one of 2 possiblities: 1 of 2 permutations.

so if you do that 10 times, you have 2^10 permutations (think of a tree diagram...how many different branches would it have!?)

For question 2 once again imagine drawing a tree diagram. After one card draw, there are 52 different branches, after two draws there are 52*52 different branches (cos each branch branches 52 times). So the total number of brances after 8 draws if 52^8

Remember that permutations are used for selection without replacement. In the coin toss, there IS replacement, because you can toss a head again after you've already tossed a head.
3. ah, actually that makes sense! thanks alot!
4. yeh does indeed willa!

exam will most certainly be something like ABCDEU vowels next to each other etc

or STATISTICS number of possiblwe arrangemwentsdtf sd jsdfn argghe hands sore

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Updated: June 8, 2004
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