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Arcsin Integral

arcsin integral.jpg

so the derivative of x.arcsin x is not difficult, the product rule giving arcsin x + x(1-x^2)^-1

The question is how can we get a hence for the integral of arcsin x itself?

Totally confused :frown:
Original post by Gmart
arcsin integral.jpg

so the derivative of x.arcsin x is not difficult, the product rule giving arcsin x + x(1-x^2)^-1

The question is how can we get a hence for the integral of arcsin x itself?

Totally confused :frown:


ddxA=B+C\frac{d}{dx}A=B+C

∫(B+C)dx=A\int (B+C) dx = A

∫Bdx=A−∫Cdx\int B dx = A - \int C dx
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Gmart
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Original post by BuryMathsTutor
ddxA=B+C\frac{d}{dx}A=B+C

∫(B+C)dx=A\int (B+C) dx = A

∫Bdx=A−∫Cdx\int B dx = A - \int C dx


Yes! Absolutely right, it is so clear the way you explain it, thank you so much :smile:

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