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    This one has niggled at me since this morning but I just remembered about it, I'm going to go to sleep so I hope theres an answer by the morning and thanks to whomever is kind enough to donate it.

    Its Q 29 in Review Exercise 2 and I can do all but part (d).

    Thanks again.
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    (Original post by Morgan)
    This one has niggled at me since this morning but I just remembered about it, I'm going to go to sleep so I hope theres an answer by the morning and thanks to whomever is kind enough to donate it.

    Its Q 29 in Review Exercise 2 and I can do all but part (d).

    Thanks again.
    If you post it up, we'll do it, but I don't have the textbook on me.
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    I hate it when people can't be arsed to type out the question.
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    The point A has coordinates (7,-1,3) and the point B has coordinates (10,-2,2) The line l has vector equation r = i + j + k + λ(3i - j + k), where λ is a real parameter.

    (a) Show that the point A lies on the line l
    (b) Find the length of AB
    (c) Find the size of the acute angle between the line l and the line segment AB, giving your answer to the nearest degree
    (d) Hence, or otherwise, calculate the perpedicular distance from B to the line l, giving your answer to 2 significant figures
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    (Original post by Philibob)
    The point A has coordinates (7,-1,3) and the point B has coordinates (10,-2,2) The line l has vector equation r = i + j + k + λ(3i - j + k), where λ is a real parameter.

    (a) Show that the point A lies on the line l
    (b) Find the length of AB
    (c) Find the size of the acute angle between the line l and the line segment AB, giving your answer to the nearest degree
    (d) Hence, or otherwise, calculate the perpedicular distance from B to the line l, giving your answer to 2 significant figures
    Ok you've got the acute angle between l and AB. You need to work out the length from where AB and l intersect and point B. As you've got the angle as well, use normal trig to work out the perpendicular distance [sin a = Perpendicular distance/ dist (AB/l intersect - B)]
 
 
 
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