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Stuck with a vectors question help is much appreciated watch

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    A tennis played serves a ball from a height of 2.51m at 18m/s in a horizontal direction. The ball just clears the net which is 1m high. Assume air resistance is negligible.

    Show that the ball takes approx 0.6s to reach the net after being served .

    Can anyone explain this set by step simply? I just started AS physics
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    The change in heigth is 1.51m. We can use the equation for vertical position:
    y = ut+1/2 gt^2
    u here is the vertical initial velocity, which is 0 cause the ball it's served horizontally. With that, it's easy to find the time for the ball to reach the net.
    t = sqare root{2*y/g}= 0.55s using g = 9.81m/s^2. Using g = 10m/s^2 will give you 0.6 s.
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