# Quick p3 questionWatch

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#1
whats the standard differential for x^m.y^n ?

edit* whoops dx was an accident
0
14 years ago
#2
whats the standard differential for x^m.y^n dx?

n e way this is what i got

u = x^m
V = Y^n

Du/dx = mx^(m-1)
Dv/dx = ny^(n-1). Dy/dx

use the product rule and solve.... a long answer which i cant get my self to type.... btw do you haf any idea how to answer the circle question i posted in the acedemic forum (P3 mock paper - 8d)
0
14 years ago
#3
(Original post by powerball)
whats the standard differential for x^m.y^n ?

edit* whoops dx was an accident
By implicit differentiation and using the product rule:

d/dx of x^m.y^n=mx^(m-1).y^n+n.x^m.y^(n-1).dy/dx
0
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