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    How do i do the inverse of f(x)=2/(x+1)
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    (Original post by theadamlevine)
    How do i do the inverse of f(x)=2/(x+1)
    Name f(x) as y. Next change the x into y and the y into x. Rearrange the equation to make y the subject of the equation and then change y to f^-1 (x ), i,e. the inverse of f(x).
    Hope this helps!

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    One of the easiest ways of doing this is saying let f(x)=y
    So now y=2/(x+1)
    Now swap the x's and the y's so the x=2/(y+1). Now solve for y
    So y+1 = 2/x. Now y=2/x - 1
    So f^-1 (x) = 2/x - 1. Always remember to replace the y with f^-1 (x).
    You could manipulate this to give f^-1(x) = (2-x)/x
    When I put f^-1(x) I don't mean 1/f(x) I mean the inverse of f(x), Just to clarify.
    Also remember that the inverse function is the reflection of the function in the line y=x.
 
 
 

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