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    Would someone be able to tell me if I got these questions right?:

    Given that B is the acute angle such that sinB=6/7, find the exact value of

    i)cosecB,
    ii)Cot^2 B

    So I got 7/6 for cosecB and 13/36 for cot^2 B. I'm pretty sure I got part 2 wrong, could you run through it if so? , I used the method where you draw out the triangle and find the angle form that.

    Thankee much
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    (Original post by what?!)
    Would someone be able to tell me if I got these questions right?:

    Given that B is the acute angle such that sinB=6/7, find the exact value of

    i)cosecB,
    ii)Cot^2 B

    So I got 7/6 for cosecB and 13/36 for cot^2 B. I'm pretty sure I got part 2 wrong, could you run through it if so? , I used the method where you draw out the triangle and find the angle form that.

    Thankee much
    I think you've got part ii) correct, you've re-arranged the trig identity equation and subbed in part i), squared it and took away 1, which was 36/36 from 49/36 which leaves you with 13/36.
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    (Original post by H.Ibrahim)
    I think you've got part ii) correct, you've re-arranged the trig identity equation and subbed in part i), squared it and took away 1, which was 36/36 from 49/36 which leaves you with 13/36.
    Yep, thanks!
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    (Original post by what?!)
    Yep, thanks!
    No problem
 
 
 
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