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# Trigonometry C3 watch

1. Would someone be able to tell me if I got these questions right?:

Given that B is the acute angle such that sinB=6/7, find the exact value of

i)cosecB,
ii)Cot^2 B

So I got 7/6 for cosecB and 13/36 for cot^2 B. I'm pretty sure I got part 2 wrong, could you run through it if so? , I used the method where you draw out the triangle and find the angle form that.

Thankee much
2. (Original post by what?!)
Would someone be able to tell me if I got these questions right?:

Given that B is the acute angle such that sinB=6/7, find the exact value of

i)cosecB,
ii)Cot^2 B

So I got 7/6 for cosecB and 13/36 for cot^2 B. I'm pretty sure I got part 2 wrong, could you run through it if so? , I used the method where you draw out the triangle and find the angle form that.

Thankee much
I think you've got part ii) correct, you've re-arranged the trig identity equation and subbed in part i), squared it and took away 1, which was 36/36 from 49/36 which leaves you with 13/36.
3. (Original post by H.Ibrahim)
I think you've got part ii) correct, you've re-arranged the trig identity equation and subbed in part i), squared it and took away 1, which was 36/36 from 49/36 which leaves you with 13/36.
Yep, thanks!
4. (Original post by what?!)
Yep, thanks!
No problem

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