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    I done this question in class the answer the teacher said is different from what I got.
    The question was:
    How many sulfite ions are present in 2.1g of anhydrous sodium sulfite?

    My answer was 2.00 x10^23.
    Is this correct?
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    (Original post by ozmo19)
    I done this question in class the answer the teacher said is different from what I got.
    The question was:
    How many sulfite ions are present in 2.1g of anhydrous sodium sulfite?

    My answer was 2.00 x10^23.
    Is this correct?
    No, it should be 1.00 x 1022
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    Work out how many moles there are in 2.1g of sodium sulfite, so 2.1 divided by the Mr of sodium sulfite. Then you know how many moles you have. Then multiply the avargadro constant by the number of moles you have.
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    (Original post by charco)
    No, it should be 1.00 x 1022
    I had this answer wrote down and I multiplied it by 2 by mistake.
    Thanks
 
 
 

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