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    Can anyone help me with this?
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    The binomial theorem says that (1+x)^n = 1 + nx + n(n-1)(x^2)/2! +
    n(n-1)(n-2)(x^3)/3! + ...
    So replace n with b and x with (ax) and then you should be able to see what to do from there.
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    What was the answer, I got a=24/11 and b=11/2 which I doubt
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    I had another go and only considered the coefficients and squared the a and managed to get more feasible results. I got a=15/2 and b=8/5.

    Oh, when I expand it using those values my x^2 value is wrong since I get 27 and not 54 so still not right.
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    (Original post by BinaryJava)
    I had another go and only considered the coefficients and squared the a and managed to get more feasible results. I got a=15/2 and b=8/5.

    Oh, when I expand it using those values my x^2 value is wrong since I get 27 and not 54 so still not right.
    You should get a=3 and b=4
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    (Original post by B_9710)
    You should get a=3 and b=4
    Yep I have managed to get that now, my 2! was getting mixed up somewhere. I guess that is what I get for doing maths at 2 AM XD
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    (Original post by b_9710)
    you should get a=3 and b=4
    thank you so much
 
 
 

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