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# AS MATHS QUESTION( giving reps) watch

1. I'm really stuck on this question, can anyone help?
A circle has the equation x^2+y^2+8x-4y-30=0 ( so the centre is (-4,2) )

Find the equation of the chord AB of the circle, which passes through X (0,18/7) such that AX=BX.

You aren't given the points A or B.
I'll be so grateful for any help.
2. X = 7
3. (Original post by Jory)
X = 7
Not meant to give full answers here.
4. Use the equation to find out the radius and work from there
5. (Original post by Megan_101)
I'm really stuck on this question, can anyone help?
A circle has the equation x^2+y^2+8x-4y-30=0 ( so the centre is (-4,2) )

Find the equation of the chord AB of the circle, which passes through X (0,18/7) such that AX=BX.

You aren't given the points A or B.
I'll be so grateful for any help.
Very good question
After finding radius which I got sqrt23 strangely , find distance between centre and x
Then using Pythagoras you can find length bx or ax same thing. Is bx (sqrt of 327)/7?

not sure what to do at that point onwards, could easily be overcomplicating this haha
6. I think it's y=-19/14x +18/7 but I'm not sure
I found the radius to be 6 then did 2+6 to get (-4,8) as A then found the gradient using that and the coordinates given
7. (Original post by Megan_101)
I'm really stuck on this question, can anyone help?
A circle has the equation x^2+y^2+8x-4y-30=0 ( so the centre is (-4,2) )

Find the equation of the chord AB of the circle, which passes through X (0,18/7) such that AX=BX.

You aren't given the points A or B.
I'll be so grateful for any help.

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Updated: September 13, 2015
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