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    cotx-cosx/1-sinx= cotx

    this is c3 nd u need to prove the left equals right side

    also
    (1+cosx)(cosecx-cotx)=sinx
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    (Original post by cheerupgrrl5:))
    cotx-cosx/1-sinx= cotx

    this is c3 nd u need to prove the left equals right side
    thwer
    also
    (1+cosx)(cosecx-cotx)=sinx
    There are always several ways of going about these!

    For the 1st one, I would start with the LHS, multiply top and bottom of the fraction by 1+sinx and then sort things out.

    For the 2nd, just multiply the bracket and see what comes out (2 terms will combine and simplify!)
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    (Original post by davros)
    There are always several ways of going about these!

    For the 1st one, I would start with the LHS, multiply top and bottom of the fraction by 1+sinx and then sort things out.

    For the 2nd, just multiply the bracket and see what comes out (2 terms will combine and simplify!)

    Ok thanks...i figured it out😄
 
 
 
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Updated: September 14, 2015
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