and minimum value of x = 1/e
for my integration i just used between e and 0, not sure if that right though.
It said bounded by x-axis (x=0) and line x = e
The vector question was so so easy though i have done p6 which makes p3 vectors very easy indeed.
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- 09-06-2004 22:36
- 09-06-2004 22:41
If its bounded by the x-axis then y=0 not x. stupid idiotic question though!!!
- 09-06-2004 22:44
oh yeah lol whoops!
what did you get for t as x get 'extremely large'
i got t = 2
i have to say their wording was not very good
- 09-06-2004 22:49
I think I got something along the lines of t=aaaaaaaaaaaaaaaaaaaaaargh my head hurts
lol i dont remember exactly, it was soemthing along the lines of 2 i think. lol i really dont remember. i am now trying to block it all out of my head so that i dont get any nightmares tonight!!!
- 09-06-2004 22:50
hehe my general solution was along the lines of...
x = 1/ [k(t-c)]
using the values, i got k as 0.5 and c as 2
- 09-06-2004 22:55
the "gets very large" that was really unmathematical, if they'd defined it a bit better i think i might have known what they were talking about. maybe some of the marks were for interpretation....
- 09-06-2004 23:23
yup, rather surprising from ocr, they're usually quite good.
you'd expect edexcel to be making those kind of loose wordings but not ocr!