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    If you had equal concentrations of hcl and h2so4 and reacted it with caco3, what would the difference be in rate?

    I thought it would be faster initially for h2so4 as it is a diprotic acid so greater h+ concentration.

    But then caso4 is produced which coats the caco3 to prevent it reacting further?

    Also, is the volume of co2 produced, in theory, double for h2so4 compared to hcl?
    Thanks
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    (Original post by PS4)
    If you had equal concentrations of hcl and h2so4 and reacted it with caco3, what would the difference be in rate?

    I thought it would be faster initially for h2so4 as it is a diprotic acid so greater h+ concentration.

    But then caso4 is produced which coats the caco3 to prevent it reacting further?

    Also, is the volume of co2 produced, in theory, double for h2so4 compared to hcl?
    Thanks
    Your thinking is good.

    The rate will very much depend on the grain size of the calcium carbonate. With powder it is unlikely that much calcium sulfate forms, but with marble chips (for example) formation of an insoluble layer of sulfate will have a major effect on the rate and even on the overall volume of gas produced.
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    (Original post by charco)
    Your thinking is good.

    The rate will very much depend on the grain size of the calcium carbonate. With powder it is unlikely that much calcium sulfate forms, but with marble chips (for example) formation of an insoluble layer of sulfate will have a major effect on the rate and even on the overall volume of gas produced.
    Thanks for your reply.

    Hypothetically should the volume of co2 produced for h2so4 be double that produce for hcl if caso4 didn't influence the reaction?
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    (Original post by PS4)
    Thanks for your reply.

    Hypothetically should the volume of co2 produced for h2so4 be double that produce for hcl if caso4 didn't influence the reaction?
    Depends on which reagent is in excess. If the carbonate is in excess then, yes.
 
 
 
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