question 12 III , http://www.ocr.org.uk/Images/61423-q...nced-level.pdf. Ty.
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hard binomial distribution question. watch
- Thread Starter
- 16-09-2015 01:00
- 16-09-2015 09:11
The probability of a randomly selected employee being part time is 17/40.
Therefore probability of two or more must be certainty minus the probability of zero or one.
P(x=0) = 0.01194...
P(x=1) = 0.07065...
One minus the above two results gives 0.917 (3 sf)