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    iii???

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    What would the effect be on the rate by doubling [X]?

    What about by doubling [Y]?

    What about by doubling one then the other? i.e. the same as doing them both at the same time.
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    If x is doubled the rate will double
    If y is doubled the rate will quadroople does that mean it will increase 6 times?
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    It goes 2x as fast and then it goes 4x as fast as that.
    OR
    It goes 4x then 2x more.

    6x? I think not.
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    Oh the rate will increase 8 times, i understand now thank you
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    Plug it into the equation. That's what it's there for, after all.
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    Plug what into the equation? I dont have a value for K
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    Since you don't have a value, try k = 1.
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    (Original post by Ismail786)
    Plug what into the equation? I dont have a value for K
    Work it through algebraically;

    r0=k*[x0]*[y0]2

    r1=k*[x1]*[y1]2 where x1=2x0

    r1=k*2[x0]*(2[y0])2

    r1=(2*22)*k*[x0][y0]2

    r1=8k*[x0][y0]2

    Ratio of r1 to r0;

    r1/r0 = (8k*[x0][y0]2) / (k*[x0]*[y0]2)

    r1/r0 = 8

    So the rate is eight times faster, and you don't need to know the rate constant.
    Obviously this is the process that takes about four seconds in a practised mind, so you don't need to write all that out ever.
 
 
 
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